PHP从目录获取单个文件名

Question

trying to get a single file from directory (alphabetically)

and the file types would be png jpeg tiff gif

final out put would be like echo firstimage.jpg nextiamge.jpg previous.img

cant get it work .. started withi this

this one i recovered from power amendments where not saved (showing work)

function getRandomFromArray($ar) {
mt_srand( (double)microtime() * 1000000 ); 
$num = array_rand($ar); 
return $ar[$num];
}

function getImagesFromDir($path) {
$images = array();
if ( $img_dir = @opendir($path) ) {
while ( false !== ($img_file = readdir($img_dir)) ) {
// checks for gif, jpg, png
if ( preg_match("/(\.gif|\.jpg|\.png)$/", $img_file) ) {
$images[] = $img_file; 
}
}
closedir($img_dir); 
}
return $images; 
echo $images;
}

$root = '/ers/m'; 
// If images not in sub directory of current directory specify root 
//$root = $_SERVER['DOCUMENT_ROOT'];

$path = ''; 

// Obtain list of images from directory 
$imgList = getImagesFromDir($root . $path);

$img = getRandomFromArray($imgList); 

what im trying to make is a slide show ... from directory but i can now output the first file..

but thats it echo "slideshow.php?nextimage.jpg"

here is basic idea
$dir = '*.jpg, *.png'; etc getfirst name from directory getnext name from directory

thanks to Rizier123 $types = array("png", "jpeg", "tiff", "gif"); $files = array();

    foreach($types as $type) {
        $files[$type] = glob("*.$type");
    }

    array_multisort($files);

    foreach($files as $key => $type) {
        if(count($type) > 0) {
            echo "Type: " . $key . " First file: " . $type[0];
        }
    }

sorry not fair being voted down i tried to save the work but we have horrible power in my country

Answer 1

This should work for you:

<?php

    $types = array("png", "jpeg", "tiff", "gif");
    $files = array();

    foreach($types as $type) {
        $files[$type] = glob("*.$type");
    }

    array_multisort($files);

    foreach($files as $key => $type) {
        if(count($type) > 0) {
            echo "Type: " . $key . " First file: " . $type[0];
        }
    }

?>

possible Output:

Type: png First file: gre.png
Type: gif First file: 1.gif

Answer 2

this one i recovered from power amendments where not saved (showing work)

function getRandomFromArray($ar) {
mt_srand( (double)microtime() * 1000000 ); 
$num = array_rand($ar); 
return $ar[$num];
}

function getImagesFromDir($path) {
$images = array();
if ( $img_dir = @opendir($path) ) {
while ( false !== ($img_file = readdir($img_dir)) ) {
// checks for gif, jpg, png
if ( preg_match("/(\.gif|\.jpg|\.png)$/", $img_file) ) {
$images[] = $img_file; 
}
}
closedir($img_dir); 
}
return $images; 
echo $images;
}

$root = '/ers/m'; 
// If images not in sub directory of current directory specify root 
//$root = $_SERVER['DOCUMENT_ROOT'];

$path = ''; 

// Obtain list of images from directory 
$imgList = getImagesFromDir($root . $path);

$img = getRandomFromArray($imgList);