过滤器选项中的逻辑运算符

Question

How to use two arguments in a filter?

var source3 = Game.spawns.Spawn1.pos.findClosest(Game.SOURCES_ACTIVE, {
    filter: function(object) {
        return object.id != source1 && source2;
    }
}).id;

Because my filter only considers the argument 'source1'...

Answer 1

Just make sure you add the comparison in the second part as well object.id != source2

var source3 = Game.spawns.Spawn1.pos.findClosest(Game.SOURCES_ACTIVE, {
    filter: function(object) {
        return object.id != source1 && object.id != source2;
    }
}).id;