为foreach（）提供的JSON无效参数

Question

I have some issue to retrieve data from JSON, it always said Invalid argument supplied for foreach() , this is the JSON in the url.php :

[{"nama":"IT SERVICE & SOLUTION","nilai":0,"periode":"11","tahun":"2014"},{"nama":"SUBDIV BUSINESS SERVICE","nilai":0,"periode":"11","tahun":"2014"},{"nama":"Data Analytics","nilai":100.1446,"periode":"11","tahun":"2014"}]

and this is my code :

<?php
$url="url.php";
$json = file_get_contents($url);
$koyim=  json_decode($json,true);
foreach($koyim as $data){
    echo $data->nilai;
    echo $data->nama;
    echo "<br/>";
}
?>

I've been trying different things to retrieve the json but still not having the result, any idea for this ?

thanks in advance

Answer 1

You need to explicitly turn json_decode output to an array. Like this:

$koyim = (array)json_decode($json);

I had exactly same issue like yours and this resolved my issue.

Answer 2

Just remove the true in the json_decode() like this:

$koyim=  json_decode($json);

Output:

0 IT SERVICE & SOLUTION
0 SUBDIV BUSINESS SERVICE
100.1446 Data Analytics

Because if you look into the manual: http://php.net/manual/en/function.json-decode.php

And take a quote from there:

assoc When TRUE, returned objects will be converted into associative arrays.

Answer 3

Please take a look at the assoc flag that you are setting to true when you call json_decode : http://php.net/manual/en/function.json-decode.php

assoc
When TRUE, returned objects will be converted into associative arrays.

When assoc flag is set to true the returned objects will be converted into associative arrays, with that being said, the way you can access your properties will be using [] not ->

it should work fine using the below code:

<?php
$url="url.php";
$json = file_get_contents($url);
$koyim=  json_decode($json,true);
foreach($koyim as $data){
    echo $data['nilai'];
    echo $data['nama'];
    echo "<br/>";
}
?>

Answer 4

Since your JSON is valid, next step is to check for PHP error in decoding.

First try this code to check error while decoding JSON:

<?php
    $url="url.php";
    $json = file_get_contents($url);
    $koyim=  json_decode($json,true);

    // Add this switch to your code
    switch (json_last_error()) {
    case JSON_ERROR_NONE:
        echo ' - No errors';
    break;
    case JSON_ERROR_DEPTH:
        echo ' - Maximum stack depth exceeded';
    break;
    case JSON_ERROR_STATE_MISMATCH:
        echo ' - Underflow or the modes mismatch';
    break;
    case JSON_ERROR_CTRL_CHAR:
        echo ' - Unexpected control character found';
    break;
    case JSON_ERROR_SYNTAX:
        echo ' - Syntax error, malformed JSON';
    break;
    case JSON_ERROR_UTF8:
        echo ' - Malformed UTF-8 characters, possibly incorrectly encoded';
    break;
    default:
        echo ' - Unknown error';
    break;
}
// end of switch

foreach($koyim as $data){
echo $data['nilai'];
echo $data['nama'];
echo "<br/>";
}
?>

Once you know the error you can search for more precise error from CONSTANT in case. Most like its 'JSON_ERROR_UTF8'.

For this you can try this code: $url = "url.php";

$json = file_get_contents($url);
$json = iconv('UTF-8', 'UTF-8//IGNORE', utf8_encode($json));

$koyim = json_decode($json,true);

Answer 5

i was have this error too, and i have solved it using this:

    $koyim = (array)json_decode($json, true);

so, your code should be like this:

    $url = "url.php";
    $json = file_get_contents($url);
    $koyim = (array)json_decode($json, true);
    foreach($koyim as $data) {
        echo $data['nilai'];
        echo $data['nama'];
        echo "<br/>";
    }