MySQL | 在特定日期使用列选择数据的最简单方法

Question

I have a table with the following structure

+-------+-------------+------+-----+---------+----------------+
| Field | Type        | Null | Key | Default | Extra          |
+-------+-------------+------+-----+---------+----------------+
| id    | int(11)     | NO   | PRI | NULL    | auto_increment |
| name  | varchar(32) | NO   |     | NULL    |                |
| time  | int(19)     | NO   |     | NULL    |                |
+-------+-------------+------+-----+---------+----------------+

time being set to a UNIX_TIMESTAMP .

If I wanted to count the amount of values with a certain name, with a time value inside a day, would it be wise to change my table & application to use DATETIME type, or is there an easy way I could select different values for the day, and do this for multiple days & names.

I am using the PDO extension of PHP to query the database, and I am currently using the following code to create the query.

$stmt = $dbh->prepare("SELECT 
  (SELECT COUNT(*) FROM `test` WHERE `name`='name' AND `time` > :time1First AND `time` < :time1Second) AS `time1`, ...");

I will be happy to try and clarify anything that is not understood from this post. It seemed clear to me, but that is probably just because I was the one who wrote it.

Answer 1

In my honest opinion, I would use a datetime column data type. They are easier to treat specially when doing queries like yours.

BTW, your query seems correct, but you'll need to enter an int representing the UNIX_TIMESTAMP.

Regards, Xavi.

Answer 2

With GROUP BY you can count all times for every name. Try this

SELECT name, COUNT(*) as time1
  FROM test
 WHERE name = 'name' 
   AND time BETWEEN :time1First AND  :time1Second
 GROUP BY name
 ORDER BY name;