[英]How to use keys from a dictionary to search for strings?
I'm writing a program which edits a text file. 我正在编写一个编辑文本文件的程序。 I intend for the program to look for duplicate strings and delete n - 1 lines of similar strings.
我打算让程序查找重复的字符串并删除n-1行相似的字符串。
Here is the script I have so far: 这是我到目前为止的脚本:
import re
fname = raw_input("File name - ")
fhand = open(fname, "r+")
fhand.read()
counts = {}
pattern = re.compile(pattern)
# This searches the file for duplicate strings and inserts them into a dictionary with a counter
# as the value
for line in fhand:
for match in pattern.findall(line):
counts.setdefault(match, 0)
counts[match] += 1
pvar = {}
#This creates a new dictionary which contains all of the keys in the previous dictionary with
# count > 1
for match, count in counts.items():
if count > 1:
pvar[match] = count
fhand.close()
count = 0
# Here I am trying to delete n - 1 instances of each string that was a key in the previous
# dictionary
with open(fname, 'r+') as fhand:
for line in fhand:
for match, count in pvar.items():
if re.search(match, line) not in line:
continue
count += 1
else:
fhand.write(line)
print count
fhand.close()
How can I make the last bit of code work? 如何使最后的代码起作用? Is it possible to use the keys from the dictionary to identify relevant lines and delete n-1 instances?
是否可以使用字典中的键来标识相关行并删除n-1个实例? Or am I doing it completely wrong?
还是我做的完全错误?
EDIT: Sample from file, this is supposed to be a list with each 'XYZ' instance being on a newline with two whitespace characters in front. 编辑:来自文件的样本,这应该是一个列表,每个“ XYZ”实例都位于换行符上,并且前面有两个空格字符。 The formatting's a bit messed up, my apologies INPUT
格式有点混乱,我很抱歉输入
-=XYZ[0:2] &
-=XYZ[0:2] &
-=XYZ[3:5] &
=XYZ[6:8] &
=XYZ[9:11] &
=XYZ[12:14] &
-=XYZ[15:17] &
=XYZ[18:20] &
=XYZ[21:23] &
OUTPUT 输出值
=XYZ[0:2] = XYZ [0:2]
EDIT 编辑
Also, could anyone explain why the last part of the code doesn't return anything? 另外,有人可以解释为什么代码的最后部分不返回任何内容吗?
Here is something without using regex, using a dictionary (so lines are unordered, probably does not matter...): 这是不使用正则表达式,使用字典的内容(因此行是无序的,可能没关系...):
#!/usr/bin/env python
import os
res = {}
with open("input.txt") as f:
for line in f.readlines():
line = line.strip()
key = line.split('[')[0].replace('-','').replace('=', '')
if key in res:
continue
res[key] = line
# res[key] = line.replace('&', '').strip()
print os.linesep.join(res.values())
This does not get rid of the trailing ampersand. 这并不能消除尾随的“&”号。 If you want to get rid of it uncomment:
如果您想摆脱它,请取消注释:
res[key] = line.replace('&', '').strip()
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