[英]matplotlib get axis-relative tick positions
I know that I can get the positions of my y-ticks by ax.get_yticks()
(btw., is that the best/correct way to get them?). 我知道我可以通过
ax.get_yticks()
获取我的y-ticks的位置(顺便说一句,这是获取它们的最佳/正确方法吗?)。 But I need the tick positions relative to the axis limits (ie, between 0 and 1). 但是我需要相对于轴限制的刻度位置(即0到1之间)。 What is the best way to get that?
最好的方法是什么? I tried
ax.get_yticks(transform=ax.transAxes)
, which does not work. 我尝试了
ax.get_yticks(transform=ax.transAxes)
,它不起作用。
This transformation can be easily done by hand: 可以轻松地手动完成此转换:
y_min, y_max = ax.get_ylim()
ticks = [(tick - y_min)/(y_max - y_min) for tick in ax.get_yticks()]
UPDATE UPDATE
To get it working with log scales, we need to employ matplotlib.transforms
. 要使其与对数刻度一起使用,我们需要使用
matplotlib.transforms
。 But transforms can only work with (x,y)
points, so we need first to complement y-ticks with some x coordinates (for example, zeros): 但是变换只能与
(x,y)
点一起使用,因此我们首先需要用一些x坐标(例如零)来补充y-ticks:
crd = np.vstack((np.zeros_like(ax.get_yticks()), ax.get_yticks())).T
Then we can transform data coodinates to display and then to axes and take y
column of it: 然后,我们可以转换数据共坐标以显示,然后转换为轴并取其
y
列:
ticks = ax.transAxes.inverted().transform(ax.transData.transform(crd))[:,1]
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