在弹出窗口中打开另一个弹出窗口？

Question

I have these two codes. "win2" is what I open first, then when I'm trying to open "win". It doesn't do anything. Please tell me what is wrong

    var win;
    function viewTicketDetails() {
        win = window.open('ViewTicketDetailsPage.aspx'
                                , 'TicketDetails'
                                , 'width=1040, height=600, innerHeight=600, location=no, menubar=no, status=no, titlebar=no, scrollbars=yes, left=0'
                                , '_blank'); 
       win.focus();
    };


    var win2;
    function viewTicketHistory() {
        win2 = window.open('AffectedUserHistoryPage.aspx'
                                , 'Ticket History'
                                , 'width=1040, height=300, innerHeight=300, location=no, menubar=no, status=no, titlebar=no, scrollbars=yes, left=0'
                                , '_blank');
        win2.focus();
    };

Answer 1

You need to write viewTicketsDetaisl() in the page from where you want to open the second window. viewTicketDetails should be written in AffectedUserHistoryPage.aspx .