[英]Using JQuery ReplaceWith on input type checkbox
I am trying to convert a table with inputs into a table of values. 我试图将带有输入的表转换为值表。 I created this javascript function that works on everything except for input with the type checkbox. 我创建了此javascript函数,该函数对除带有类型复选框的输入之外的所有东西都有效。
This is my current function : 这是我当前的功能:
function PopulateHidden() {
$('#Units input').replaceWith(function () {
return this.value;
});
$('#Units select').replaceWith(function () {
return this.value;
});
var html = $("#Units").html();
$('#<%=UnitTableHtml.ClientID%>').val(html);
}
i have tried doing various version of this method: 我试图做这种方法的各种版本:
$(".chk").replaceWith(function () {
alert(this.html());
if (this.prop('checked') == true) {
alert("YES");
return "Yes";
};
return "No";
});
But I keep getting the value of the textboxes as "on" rather than a true/false. 但是我一直将文本框的值设置为“ on”,而不是true / false。 I want the value to be Yes or No but it is not getting inside the if statement. 我希望该值为Yes或No,但它不在if语句内。 Any reason why I cannot get the value of the checkbox as a boolean? 为什么无法将复选框的值作为布尔值获取任何原因?
Here is how i defined the checkbox: 这是我定义复选框的方式:
<input type="checkbox" class="chk" style="width:20px;height:20px;"/>
All praise Jasper as I was building this fiddle with the same suggestion: Needs $(this)
instead of this
在我用相同的建议构建此小提琴时,所有人都赞扬了贾斯珀:需要$(this)
而不是this
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