使用Java的AES_ENCRYPT和AES_DECRYPT

Question

I have table mm with field id,name and sal

I inserted encrypted value in the DB using the AES_ENCRYPT

psmt = con.prepareStatement("insert into mm values("+id+",AES_ENCRYPT('"+name+"','"+key+"'),AES_ENCRYPT('"+sal+"','"+key+"'))");

It is working properly

but when i am trying to retrieve these values using AES_DECRYPT

rs = st.executeQuery("select id,AES_DECRYPT(name,'"+key+"'),AES_DECRYPT(sal,'"+key+"') FROM mm WHERE id="+rs.getInt(1)+"");

When i am applying query on mysql console it work properly.

but when apply using java code it gives values like

| 1| [B@1f0690a| [B@803365 |

Why i am getting these values instead of the original values ?

Answer 1

A toString() on a byte-array does not return the content of the byte array, but [B@ followed by the identity hashcode of the byte array. In your insert you did not use the content of key as the key, but the toString -value. You need to use a PreparedStatement with a parametrized query, and set the values using setBytes :

psmt = con.prepareStatement("insert into mm values (?, AES_ENCRYPT(?, ?), AES_ENCRYPT(?, ?))");
psmt.setInt(1, id);
psmt.setString(2, name);
psmt.setBytes(3, key);
psmt.setstring(4, sal);
psmt.setBytes(5, key);

And do the same for your select query.

You should never concatenate values into your query. It will make you vulnerable to SQL injection.

Answer 2

Change your process sequence.

First, just select your value from table.

From your eg. --> | 1| [B@1f0690a| [B@803365 |

Second, decrypt these two column using AES_DECRYPT.