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具有日期条件逻辑的CASE表达式

[英]CASE Expression with Dates conditional Logic

I have a logic in a query for a report that determines the number of days passed, excluding weekends. 在查询报表时,我有一个逻辑来确定通过的天数,不包括周末。 There are 2 possible start dates - the original receipt date or the date of a re-submit (if it exists). 有两个可能的开始日期-原始接收日期或重新提交的日期(如果存在)。 I am able to correctly calculate this using the following CASE statement 我可以使用以下CASE语句正确计算此值

  CASE WHEN [ResubmitReceivedDate] IS NULL THEN
  (SELECT
        (DATEDIFF(dd, [OriginalReceivedDate] , [AnalysisDate]) + 1)
        -(DATEDIFF(wk,[OriginalReceivedDate] , [AnalysisDate]) * 2)
        -(CASE WHEN DATENAME(dw, [OriginalReceivedDate] ) = 'Sunday' THEN 1 ELSE 0 END)
        -(CASE WHEN DATENAME(dw, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END) 
    )
    ELSE
    (SELECT
        (DATEDIFF(dd, [ResubmitReceivedDate], [AnalysisDate]) + 1)
        -(DATEDIFF(wk, [ResubmitReceivedDate], [AnalysisDate]) * 2)
        -(CASE WHEN DATENAME(dw, [ResubmitReceivedDate]) = 'Sunday' THEN 1 ELSE 0 END)
        -(CASE WHEN DATENAME(dw, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END) 
    ) 

However, there are some instances when the [AnalysisDate] comes before the [ResubmitReceivedDate] , and in these instances, the [OriginalReceivedDate] should still be used even though a [ResubmitReceivedDate] exists. 但是,在某些情况下[AnalysisDate][ResubmitReceivedDate]之前,并且在这些情况下,即使[ResubmitReceivedDate]存在,仍应使用[OriginalReceivedDate]

How can I add this logic to the above CASE statement? 如何将这种逻辑添加到上面的CASE语句中?

Seems like the simplest solution would just be to add another When condition. 似乎最简单的解决方案只是添加另一个When条件。 Something like this: 像这样:

WHEN DateDiff(day, [ResubmitReceivedDate], [AnalysisDate]) > -1 THEN
    (Select
        (DATEDIFF(day, [OriginalReceivedDate] , [AnalysisDate]) + 1)
        -(DATEDIFF(week,[OriginalReceivedDate] , [AnalysisDate]) * 2)
        -(CASE WHEN DATENAME(weekday, [OriginalReceivedDate] ) = 'Sunday' THEN 1 ELSE 0 END)
        -(CASE WHEN DATENAME(weekday, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END)
    )

Which would make your final case 这将使您成为最后的案例

Case
     WHEN [ResubmitReceivedDate] IS NULL THEN
        (Select
            (DATEDIFF(day, [OriginalReceivedDate] , [AnalysisDate]) + 1)
            -(DATEDIFF(week,[OriginalReceivedDate] , [AnalysisDate]) * 2)
            -(CASE WHEN DATENAME(weekday, [OriginalReceivedDate] ) = 'Sunday' THEN 1 ELSE 0 END)
            -(CASE WHEN DATENAME(weekday, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END)
        )
     WHEN DateDiff(day, [ResubmitReceivedDate], [AnalysisDate]) < -1 THEN
        (Select
            (DATEDIFF(day, [OriginalReceivedDate] , [AnalysisDate]) + 1)
            -(DATEDIFF(week,[OriginalReceivedDate] , [AnalysisDate]) * 2)
            -(CASE WHEN DATENAME(weekday, [OriginalReceivedDate] ) = 'Sunday' THEN 1 ELSE 0 END)
            -(CASE WHEN DATENAME(weekday, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END)
        )
    Else
        (SELECT
            (DATEDIFF(day, [ResubmitReceivedDate], [AnalysisDate]) + 1)
            -(DATEDIFF(week, [ResubmitReceivedDate], [AnalysisDate]) * 2)
            -(CASE WHEN DATENAME(weekday, [ResubmitReceivedDate]) = 'Sunday' THEN 1 ELSE 0 END)
            -(CASE WHEN DATENAME(weekday, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END) 
        )
End

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