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Spring REST - 创建 ZIP 文件并将其发送到客户端

[英]Spring REST - create ZIP file and send it to the client

I want to create a ZIP file that contains my archived files that I received from the backend, and then send this file to a user.我想创建一个 ZIP 文件,其中包含我从后端收到的存档文件,然后将此文件发送给用户。 For 2 days I have been looking for the answer and can't find proper solution, maybe you can help me :) 2天来我一直在寻找答案,但找不到合适的解决方案,也许你可以帮助我:)

For now, the code is like this (I know I shouldn't do it all in the Spring controller, but don't care about that, it is just for testing purposes, to find the way to make it works):现在,代码是这样的(我知道我不应该在 Spring 控制器中做所有的事情,但不要在意,它只是为了测试目的,找到让它工作的方法):

    @RequestMapping(value = "/zip")
    public byte[] zipFiles(HttpServletResponse response) throws IOException {
        // Setting HTTP headers
        response.setContentType("application/zip");
        response.setStatus(HttpServletResponse.SC_OK);
        response.addHeader("Content-Disposition", "attachment; filename=\"test.zip\"");

        // Creating byteArray stream, make it bufferable and passing this buffer to ZipOutputStream
        ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
        BufferedOutputStream bufferedOutputStream = new BufferedOutputStream(byteArrayOutputStream);
        ZipOutputStream zipOutputStream = new ZipOutputStream(bufferedOutputStream);

        // Simple file list, just for tests
        ArrayList<File> files = new ArrayList<>(2);
        files.add(new File("README.md"));

        // Packing files
        for (File file : files) {
            // New zip entry and copying InputStream with file to ZipOutputStream, after all closing streams
            zipOutputStream.putNextEntry(new ZipEntry(file.getName()));
            FileInputStream fileInputStream = new FileInputStream(file);

            IOUtils.copy(fileInputStream, zipOutputStream);

            fileInputStream.close();
            zipOutputStream.closeEntry();
        }

        if (zipOutputStream != null) {
            zipOutputStream.finish();
            zipOutputStream.flush();
            IOUtils.closeQuietly(zipOutputStream);
        }
        IOUtils.closeQuietly(bufferedOutputStream);
        IOUtils.closeQuietly(byteArrayOutputStream);

        return byteArrayOutputStream.toByteArray();
    }

But the problem is, that using the code, when I enter the URL localhost:8080/zip , I get a file test.zip.html instead of .zip file.但问题是,使用代码,当我输入 URL localhost:8080/zip时,我得到一个文件test.zip.html而不是.zip文件。

When I remove .html extension and leave just test.zip it opens correctly.当我删除.html扩展名并仅保留test.zip时,它会正确打开。 So my questions are:所以我的问题是:

  • How to avoid returning this .html extension?如何避免返回此.html扩展名?
  • Why is it added?为什么要添加它?

I have no idea what else can I do.我不知道我还能做什么。 I was also trying replace ByteArrayOuputStream with something like:我还尝试将ByteArrayOuputStream替换为:

OutputStream outputStream = response.getOutputStream();

and set the method to be void so it returns nothing, but It created .zip file which was damaged?并将方法设置为无效,因此它不返回任何内容,但它创建了损坏的.zip文件?

On my MacBook after unpacking the test.zip I was getting test.zip.cpgz which was again giving me test.zip file and so on.在我的 MacBook 上解压test.zip后,我得到了test.zip.cpgz ,它再次给了我test.zip文件等等。

On Windows the .zip file was damaged as I said and couldn't even open it.正如我所说,在 Windows 上,.zip 文件已损坏,甚至无法打开。

I also suppose, that removing .html extension automatically will be the best option, but how?我还认为,自动删除.html扩展名将是最好的选择,但是如何呢?

Hope it is no as hard as It seems to be :)希望它不像看起来那么难:)
Thanks谢谢

The problem is solved.问题已经解决了。

I replaced:我更换了:

response.setContentType("application/zip");

with:和:

@RequestMapping(value = "/zip", produces="application/zip")

And now I get a clear, beautiful .zip file.现在我得到了一个清晰、漂亮的.zip文件。


If any of you have either better or faster proposition, or just want to give some advice, then go ahead, I am curious.如果你们中的任何人有更好或更快的提议,或者只是想提供一些建议,那么请继续,我很好奇。

@RequestMapping(value="/zip", produces="application/zip")
public void zipFiles(HttpServletResponse response) throws IOException {

    //setting headers  
    response.setStatus(HttpServletResponse.SC_OK);
    response.addHeader("Content-Disposition", "attachment; filename=\"test.zip\"");

    ZipOutputStream zipOutputStream = new ZipOutputStream(response.getOutputStream());

    // create a list to add files to be zipped
    ArrayList<File> files = new ArrayList<>(2);
    files.add(new File("README.md"));

    // package files
    for (File file : files) {
        //new zip entry and copying inputstream with file to zipOutputStream, after all closing streams
        zipOutputStream.putNextEntry(new ZipEntry(file.getName()));
        FileInputStream fileInputStream = new FileInputStream(file);

        IOUtils.copy(fileInputStream, zipOutputStream);

        fileInputStream.close();
        zipOutputStream.closeEntry();
    }    

    zipOutputStream.close();
}
@RequestMapping(value="/zip", produces="application/zip")
public ResponseEntity<StreamingResponseBody> zipFiles() {
    return ResponseEntity
            .ok()
            .header("Content-Disposition", "attachment; filename=\"test.zip\"")
            .body(out -> {
                var zipOutputStream = new ZipOutputStream(out);

                // create a list to add files to be zipped
                ArrayList<File> files = new ArrayList<>(2);
                files.add(new File("README.md"));

                // package files
                for (File file : files) {
                    //new zip entry and copying inputstream with file to zipOutputStream, after all closing streams
                    zipOutputStream.putNextEntry(new ZipEntry(file.getName()));
                    FileInputStream fileInputStream = new FileInputStream(file);

                    IOUtils.copy(fileInputStream, zipOutputStream);

                    fileInputStream.close();
                    zipOutputStream.closeEntry();
                }

                zipOutputStream.close();
            });
}

I am using REST Web Service of Spring Boot and I have designed the endpoints to always return ResponseEntity whether it is JSON or PDF or ZIP and I came up with the following solution which is partially inspired by denov's answer in this question as well as another question where I learned how to convert ZipOutputStream into byte[] in order to feed it to ResponseEntity as output of the endpoint.我正在使用Spring BootREST Web Service ,并且我将端点设计为始终返回ResponseEntity ,无论它是JSONPDF还是ZIP ,我想出了以下解决方案,该解决方案部分受到denov's answer在这个问题和另一个问题中的回答的启发我在那里学习了如何将ZipOutputStream转换为byte[]以便将其作为端点的输出提供给ResponseEntity

Anyway, I created a simple utility class with two methods for pdf and zip file download无论如何,我创建了一个简单的实用程序类,有两种方法用于下载pdfzip文件

@Component
public class FileUtil {
    public BinaryOutputWrapper prepDownloadAsPDF(String filename) throws IOException {
        Path fileLocation = Paths.get(filename);
        byte[] data = Files.readAllBytes(fileLocation);

        HttpHeaders headers = new HttpHeaders();
        headers.setContentType(MediaType.parseMediaType("application/pdf"));
        String outputFilename = "output.pdf";
        headers.setContentDispositionFormData(outputFilename, outputFilename);
        headers.setCacheControl("must-revalidate, post-check=0, pre-check=0");

        return new BinaryOutputWrapper(data, headers); 
    }

    public BinaryOutputWrapper prepDownloadAsZIP(List<String> filenames) throws IOException {
        HttpHeaders headers = new HttpHeaders();
        headers.setContentType(MediaType.parseMediaType("application/zip"));
        String outputFilename = "output.zip";
        headers.setContentDispositionFormData(outputFilename, outputFilename);
        headers.setCacheControl("must-revalidate, post-check=0, pre-check=0");

        ByteArrayOutputStream byteOutputStream = new ByteArrayOutputStream();
        ZipOutputStream zipOutputStream = new ZipOutputStream(byteOutputStream);

        for(String filename: filenames) {
            File file = new File(filename); 
            zipOutputStream.putNextEntry(new ZipEntry(filename));           
            FileInputStream fileInputStream = new FileInputStream(file);
            IOUtils.copy(fileInputStream, zipOutputStream);
            fileInputStream.close();
            zipOutputStream.closeEntry();
        }           
        zipOutputStream.close();
        return new BinaryOutputWrapper(byteOutputStream.toByteArray(), headers); 
    }
}

And now the endpoint can easily return ResponseEntity<?> as shown below using the byte[] data and custom headers that is specifically tailored for pdf or zip .现在,端点可以使用专门为pdfzip定制的byte[]数据和自定义标头轻松返回ResponseEntity<?> ,如下所示。

@GetMapping("/somepath/pdf")
public ResponseEntity<?> generatePDF() {
    BinaryOutputWrapper output = new BinaryOutputWrapper(); 
    try {
        String inputFile = "sample.pdf"; 
        output = fileUtil.prepDownloadAsPDF(inputFile);
        //or invoke prepDownloadAsZIP(...) with a list of filenames
    } catch (IOException e) {
        e.printStackTrace();
        //Do something when exception is thrown
    } 
    return new ResponseEntity<>(output.getData(), output.getHeaders(), HttpStatus.OK); 
}

The BinaryOutputWrapper is a simple immutable POJO class I created with private byte[] data; BinaryOutputWrapper是一个简单的不可变POJO类,我使用private byte[] data; and org.springframework.http.HttpHeaders headers;org.springframework.http.HttpHeaders headers; as fields in order to return both data and headers from utility method.作为字段,以便从实用程序方法返回dataheaders

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