PHP-如何读取图片值并使其可被浏览器查看？

Question

I have JPEG/PNG small file which is stored in the mysql database field picture as following:

  $fdata = '';
  if (isset($_FILES['picture']) && $_FILES['picture']['size'] > 0) {
    $tmpName  = $_FILES['picture']['tmp_name'];  
    $fp      = fopen($tmpName, 'r');
    $fdata = fread($fp, filesize($tmpName));
    $fdata = addslashes($fdata);
    fclose($fp);
    //$sl = "INSERT INTO image (image)VALUES ( '$data')", $connection);
    print "Thank you, your file has been uploaded.";        
  } else {
    print "No image selected/uploaded";        
  }

  // Update the table 
  $this->db->update('users', 
                    array('password' => $_POST['password'], 
                          'picture' => $fdata), 
                    array('username=?' => $ouser )); 

But problem is now how do i output that "picture field" value from the database into real picture for web browsers?

EDIT 1:

Simply echo does not render the picture in browser

EDIT 2:

  public function pictureshowAction() {  
    $this->_helper->layout()->disableLayout();
    $this->_helper->viewRenderer->setNoRender();
    $this->_response->setHeader('Access-Control-Allow-Origin', '*');
    $this->db = Application_Model_Db::db_load();        
    $ouser = $_GET['ousername'];

    $sql = "select *From users where username='{$ouser}' limit 1";
    $result = $this->db->fetchAll($sql);
    if (count($result) > 0 ) {
      $picture  = $result[0]['picture'];     
      //$content = $picture; 
      $content = stripslashes($picture);
    } else {
      $content = '';
    }

    //echo $content;    

    $this->getResponse()
            ->setHeader('Content-Type', 'image/jpg')
            ->setBody($content)
            ->sendResponse();    
    exit;
  }   

Answer 1

Very easy, let's say your content type was png you first need to send a proper header to browser

header('Content-type: image/png');

Then simply output your picture content

echo $pictureContentFromDatabase;

What your screenshot shows is caused by the fact that you did not send a proper Content Type header telling the browser what your server is sending is an image, once you fix that it will be fine. And you dont have to addslashes for output, that will render the image useless. So echo the content without addslashes