[英]MySQL Multiple Joins from 3 Tables
I need to select all records from assets_tbl (A). 我需要从asset_tbl(A)中选择所有记录。 Included with these records I need to have any lightboxes (
lightbox_name
) that are linked to the asset_id
from assets_tbl
where author = "scott@co.com"
OR authorized_viewers
includes "scott@co.com"
包括在这些记录中,我需要具有任何链接到
asset_id
的assets_tbl
灯箱( lightbox_name
),其中author = "scott@co.com"
或authorized_viewers
包括"scott@co.com"
I think this is close to what I need but it returns multiple rows of the same record: 我认为这接近我的需要,但它返回同一记录的多行:
SELECT
A.*,
C.lightbox_name,
C.author,
C.authorized_viewers
FROM
media_tbl A
LEFT JOIN lightbox_assets_tbl B ON A.asset_id = B.asset_id
LEFT JOIN lightboxes_tbl C
ON B.lightbox_id = C.id
AND C.author = "scott@co.com"
LEFT JOIN lightboxes_tbl D ON D.authorized_viewers LIKE "scott@co.com"
ORDER BY A.id DESC
Here are the tables: 表格如下:
lightboxes_tbl
+-----+----------------+---------------+---------------------+
|id |lightbox_name |author |authoried_viewers |
+-----+----------------+---------------+---------------------+
|100 | aircraft-types |scott@co.com |jon@co.com,aj@co.com |
|101 | maintenance |nicole@co.com |jon@co.com |
|102 | ramp |nicole@co.com |scott@co.com |
+-----+----------------+---------------+---------------------+
lightbox_assets_tbl
+-----+-------------+-------------+---------------+----------+
|id |lightbox_id |asset_name |asset_path | asset_id |
+-----+-------------+-------------+---------------+----------+
|1 |100 |a321.jpg |project1/imgs/ | 3700 |
|2 |100 |b757.jpg |project1/imgs/ | 3444 |
|3 |101 |FlyBy.swf |project4/imgs/ | 1444 |
|4 |102 |Door_757.swf |project5/imgs/ | 3701 |
+-----+-------------+-------------+---------------+----------+
assets_tbl
+-----+---------------------+-------------------------------------+
|asset_id |asset_name | asset_location |
+-----------+---------------------+-------------------------------+
|3700 |a321.jpg |Libraries\Library_Media\Images |
|200 |757_Taxi.swf |Libraries\Library_Media\Images |
|3444 |b757.jpg |Libraries\Library_Media\Images |
|1444 |FlyBy.swf |Libraries\Library_Media\Images |
|3701 |Door_757.swf |Libraries\Library_Media\Images |
+----------+---------------------+--------------------------------+
Here are the expected RESULTS of the query: 以下是查询的预期结果:
+-----------+---------------------+-------------------------------+------------------+-------------+------------------------+
|asset_id |asset_name | asset_location |lightbox_name | author | authorized_viewers |
+-----------+---------------------+-------------------------------+------------------+-------------+------------------------+
|3700 |a321.jpg |Libraries\Library_Media\Images |aircraft-types |scott@co.com |jon@co.com,aj@co.com |
+-----------+---------------------+-------------------------------+------------------+-------------+------------------------+
|200 |757_Taxi.swf |Libraries\Library_Media\Images |NULL |NULL |NULL |
+-----------+---------------------+-------------------------------+------------------+-------------+------------------------+
|3444 |b757.jpg |Libraries\Library_Media\Images |aircraft-types |scott@co.com |jon@co.com,aj@co.com |
+-----------+---------------------+-------------------------------+------------------+-------------+------------------------+
|1444 |FlyBy.swf |Libraries\Library_Media\Images |NULL |NULL |NULL |
+-----------+---------------------+-------------------------------+------------------+-------------+------------------------+
|3701 |Door_757.swf |Libraries\Library_Media\Images |ramp |nicole@co.com|scott@co.com |
+----------+---------------------+--------------------------------+------------------+-------------+------------------------+
Thanks! 谢谢!
I'm wondering why you need two joins to the lightboxes_tbl
table. 我想知道为什么您需要两次连接
lightboxes_tbl
表。 It seems like the second reference to that table (alias D
) is unnecessary. 似乎第二次引用该表(别名
D
)是不必要的。 Seems like you could just use an OR
. 似乎您可以只使用
OR
。
As a demonstration, replicating the predicates in your query: 作为演示,复制查询中的谓词:
LEFT JOIN lightboxes_tbl C
ON B.lightbox_id = C.id
AND ( C.author = 'scott@co.com'
OR C.authorized_viewers = 'scott@co.com'
)
But given that authorized_user
contains a comma separated list (ACCKKK!!!), I suspect you really want to look for an exact match to an item in the comma separated list. 但是,鉴于
authorized_user
包含逗号分隔的列表(ACCKKK !!!),我怀疑您真的想在逗号分隔的列表中查找与某项的完全匹配。 The LIKE
comparison that currently have is equivalent to an equals comparison (to the entire contents of authorized_viewers
column). 当前具有的
LIKE
比较等效于等于比较(与authorized_viewers
列的全部内容相同)。 You could add '%'
wildcard characters to search for the value as part of the string... 您可以添加
'%'
通配符来搜索值作为字符串的一部分...
But that approach is will also match strings containing eg ebscott@co.com
, which may not be what you really want. 但是这种方法还将匹配包含
ebscott@co.com
字符串,这可能并不是您真正想要的。
You could use the FIND_IN_SET
function to find an exact match within the comma separated list... 您可以使用
FIND_IN_SET
函数在逗号分隔的列表中找到完全匹配的内容...
LEFT JOIN lightboxes_tbl C
ON B.lightbox_id = C.id
AND ( C.author = 'scott@co.com'
OR FIND_IN_SET('scott@co.com',C.authorized_viewers)
)
Storing comma separated lists is a SQL anti-pattern. 存储逗号分隔的列表是一种SQL反模式。 I recommend Bill Karwin's book: SQL Anti-Patterns: Avoiding the Pitfalls of Database Programming
我推荐Bill Karwin的书: SQL反模式:避免数据库编程的陷阱
http://www.amazon.com/SQL-Antipatterns-Programming-Pragmatic-Programmers/dp/1934356557 http://www.amazon.com/SQL-Antipatterns-Programming-Pragmatic-Programmers/dp/1934356557
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