[英]Notepad++ Regex - Replace a blank space in dates
I have a large export file from a legacy computer system.我有一个来自旧计算机系统的大型导出文件。 The dates that get exported have a
[space]
instead of a 0
for all single digit days or months:对于所有个位数的天或月,导出的日期都有一个
[space]
而不是0
:
1/ 1/2015
(dd/MM/yyyy) 1/ 1/2015
(日/月/年)
The first space is not a problem but the second space is.第一个空间不是问题,但第二个空间是。
I have tried to search and replace /[space]
but this will replace any occurrences of /[space]
in the data file - not only in dates.我试图搜索和替换
/[space]
但这将替换数据文件中出现的任何/[space]
- 不仅仅是日期。
I have also tried to use regex find and replace as follows:我还尝试使用正则表达式查找和替换如下:
Find: / [0-9]/[0-9]+
查找:
/ [0-9]/[0-9]+
Replace: /0[0-9]/[0-9]+
替换:
/0[0-9]/[0-9]+
The intended out come should be:预期的结果应该是:
Original: 1/ 1/2015
原文:
1/ 1/2015
New: 1/01/2015
新:
1/01/2015
However I got:但是我得到了:
Actual: 1/0[0-9]/[0-9]+
实际:
1/0[0-9]/[0-9]+
Is this even possible in Notepad++ or do I have to use MS Excel?这甚至可以在 Notepad++ 中实现还是我必须使用 MS Excel?
Thanks谢谢
Could you try replacing (?<=/) (?=[0-9]/[0-9]+)
with nothing (or 0, if you want padded single digit dates)?您可以尝试用空替换
(?<=/) (?=[0-9]/[0-9]+)
(或 0,如果您想要填充个位数的日期)? Works in Sublime, haven't tested NP++.在 Sublime 中工作,尚未测试 NP++。
Try this, was working perfectly in my editor.试试这个,在我的编辑器中完美运行。
Find what: (\\d/)\\s(\\d/\\d{4})
找出什么:
(\\d/)\\s(\\d/\\d{4})
Replace with: $10$2
替换为:
$10$2
The explanation of regex and output can be found in below picture.正则表达式和输出的解释可以在下图中找到。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.