[英]Convert char to const char* String Insert C++
I have a problem with String Insertion
because, I can not add a char, just a const char. 我对
String Insertion
有问题,因为我不能添加char,只能添加const char。 How can i easily convert it? 我如何轻松转换它?
The compiler just accept like this: 编译器只是这样接受:
b.insert(i,"a");
But i want like this: 但我想这样:
b.insert(i,b[ii]);
Full Code: 完整代码:
#include <stdio.h>
#include <string.h>
#include <string>
#include <iostream>
using namespace std;
int main()
{
string a,b;
int aa=0;
cin >> a;
b=a;
for(int i=0;i<a.length()+1;i++)
{
for(int ii=0;ii<a.length();ii++)
{
b.insert(i,a[ii]);
if (b == string(b.rbegin(), b.rend()))
{
cout << b << endl;aa=1;
break;
}
b.erase (b.begin()+i);
}
if(aa=1)break;
}
if(aa==0)
cout << "NA" << endl;
return 0;
}
See the documentation for std::string::insert
. 请参阅
std::string::insert
的文档。 The version that takes a single char
also needs a count argument. 采用单个
char
的版本也需要一个count参数。
b.insert(i,1,b[ii]);
You should use the following overload of std::string::insert
: 您应该使用以下
std::string::insert
重载:
basic_string& insert( size_type index, size_type count, CharT ch );
See http://en.cppreference.com/w/cpp/string/basic_string/insert 参见http://en.cppreference.com/w/cpp/string/basic_string/insert
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