如何在 AWS Elastic Beanstalk 上配置我的 WSGI 应用程序的名称？

Question

My Python web application is called app

# example.py
import flask

app = flask.Flask(__name__.split('.')[0])

and when I attempt to launch it on AWS-EB using

# run.py (set correctly with WSGIPath)
from example import app

if __name__ == "__main__":
    app.run()

I get

mod_wsgi (pid=22473): Target WSGI script '/opt/python/current/app/run.py' 
    does not contain WSGI application 'application'.

How to I tell AWS that my application instance is called app ?

Answer 1

mod_wsgi expects variable called application . Try to do something like this

from example import app as application

Note: don't do application.run() . It is not needed.

Answer 2

While the WSGIPath can be configured. Beanstalk still expects the app variable to be named as 'application'.

A simple workaround for small single file python apps can be

from flask import Flask

app = Flask(__name__)
application = app # For beanstalk

You can keep the rest of the code as is. You just need to add that single line application = app