[英]Java: Pick out multiple elements in Linked list
I have a linked list of classes which contain 3 strings and a double. 我有一个包含3个字符串和一个double的类的链接列表。 I want to collect the total value of each double in the list.
我想收集列表中每个双精度值的总和。 For example
例如
LinkedList<Person> L = new LinkedList<Person>();
Person p1 = new Person("Fee","Foo","Bar", 1.2);
Person p2 = new Person("Fi","Fi","Fo", 2.5);
L.add(p1);
L.add(p2);
I would want to find and add up 1.2, and 2.5. 我想找到并加起来1.2和2.5。 I'm assuming I should use ListIterator, but how do I tell it to add each found double value to the total?
我假设我应该使用ListIterator,但是如何告诉它将找到的每个double值加到总数中呢?
Just use a for loop over the persons: 只需对人员使用for循环:
double sum = 0;
for(Person p : L)
sum += p.getDouble();
System.out.print(sum);
You have couple of options to iterate over it 您有几个选择可以对其进行迭代
A) Using iterators as asked A)根据要求使用迭代器
Person person = new Person();
ListIterator<Person> listIterator = L.listIterator();
while (listIterator.hasNext()) {
person = listIterator.next();
double value = person.getDoubleAttribute();
}
B) Use a for-each
loop as suggested in other answer: B)按照其他答案中的建议使用
for-each
循环:
for(Person person : L){
double value = person.getDoubleAttribute();
}
PS: is highly discouraged to start Java
variables or attributes by UPPERCASE
PS:强烈建议不要使用
UPPERCASE
来启动Java
变量或属性
You can iterate over the list, get the double property of each Person and sum them, or you can use Java 8 Streams : 您可以遍历列表,获取每个Person的double属性并对它们求和,或者可以使用Java 8 Streams:
double sum = L.stream().mapToDouble(Person::getDoubleProperty).sum();
Where getDoubleProperty
stands for the name of a method in the Person
class returning the double value. 其中
getDoubleProperty
代表Person
类中返回双getDoubleProperty
值的方法的名称。
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