Python 3.4：在列表中将“ 0x”替换为“ \\ x”

Question

Hi I want to replace "0x" with "\\x" in this list:

['0x50', '0x0', '0x0', '0x0']

I tried it with this list comprehension:

result = ['0x50', '0x0', '0x0', '0x0']
result = [x.replace("0x","\x") for x in result]

But it gives me this Error:

(unicode error)"unicodeescape" codex cant decode byte in position 0-1: truncated \xXX escape

How can I change "0x" and "\\x" now?

Answer 1

Make it a raw string as in

>>> l = ['0x50', '0x0', '0x0', '0x0']
>>> [i.replace('0x',r'\x') for i in l]
['\\x50', '\\x0', '\\x0', '\\x0']

Or double-escape \\ as in

>>> [i.replace('0x','\\x') for i in l]
['\\x50', '\\x0', '\\x0', '\\x0']