如何使用PHP Regex / preg_match提取以下信息？

Question

I have the following HTML and I need to extract the URL inside VALUE

<param name="movie" value="http://domain.com/path/to/file.swf" />

I tried the following, with no success.

preg_match("'<param name=\"movie\" value=\"(.*?)\" />si'", $source,  $url); 
echo $url[1];

What am I doing wrong?

Answer 1

If you really want to use preg_match you can do:

preg_match('/<param name=\"movie\" value=\"(.*?)\" \/>/is', $source, $url);
echo $url[1]

Problem was with not escaping a / symbol at the end of a tag and you have " and ' next to each other without a reason probably.

Answer 2

My, correct variant:

$source = '<param name="movie" value="http://domain.com/path/to/file.swf" />';

preg_match('!<param name="movie" value="(.*?)"!U', $source,  $url); 
echo $url[1];

The result:

http://domain.com/path/to/file.swf

Note the modifier U which means Ungreedy , it allows .* to be compact and not return more than we actually need.