[英]Returning multiple index values from an array using Javascript
I have an array containing the individual letters of a word and i want to search the array to return the index values of certain letters. 我有一个包含单词的各个字母的数组,我想搜索该数组以返回某些字母的索引值。 However, if the word contains more a letter more than once (such as 'tree') the programme only returns one index value.
但是,如果单词包含多个字母(例如“ tree”),则该程序仅返回一个索引值。
This is a sample of the code: 这是代码示例:
var chosenWord = "tree";
var individualLetters = chosenWord.split('');
var isLetterThere = individualLetters.indexOf(e);
console.log(isLetterThere);
this code will return the number '2', as that is the first instance of the letter 'e'. 该代码将返回数字“ 2”,因为这是字母“ e”的第一个实例。 How would i get it to return 2 and 3 in the integer format, so that i could use them to replace items in another array using the .splice function.
我将如何获取它以整数格式返回2和3,以便可以使用它们使用.splice函数替换另一个数组中的项目。
indexOf
takes a second parameter, as the position where it should start searching from. indexOf
采用第二个参数作为应从其开始搜索的位置。
So my approach would be: 所以我的方法是:
function findLetterPositions(text, letter) {
var positions = new Array(),
pos = -1;
while ((pos = text.indexOf(letter, pos + 1)) != -1) {
positions.push(pos);
}
return positions;
}
console.log(findLetterPositions("Some eerie eels in every ensemble.", "e"));
You could write a function like this: 您可以编写如下函数:
function indexesOf(myWord, myLetter)
{
var indexes = new Array();
for(var i = 0; i < myWord.length; i++)
{
if(myWord.charAt(i) == myLetter)
{
indexes.push(i);
}
}
return indexes;
}
console.log(indexesOf("tree", "e"));
Loop through it as here: 如下循环:
var chosenWord = "tree"; var specifiedLetter = "e"; var individualLetters = chosenWord.split(''); var matches = []; for(i = 0;i<individualLetters.length;i++){ if(individualLetters[i] == specifiedLetter) matches[matches.length] = i; } console.log(matches);
An alternative using string methods. 使用字符串方法的替代方法。
var str = "thisisasimpleinput"; var cpy = str; var indexes = []; var n = -1; for (var i = cpy.indexOf('i'); i > -1; i = cpy.indexOf('i')) { n += i; n++; indexes.push(n); cpy = cpy.slice(++i); } alert(indexes.toString());
var getLetterIndexes = function(word, letter) {
var indexes = [];
word.split("").forEach(function(el, i) {
el === letter && indexes.push(i);
});
return indexes;
};
getLetterIndexes("tree", "e"); // [2, 3]
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