PHP创建嵌套数组并使用json_encode返回

Question

I have the following, and while $data['details'] is being populated OK, there should be three results in $data['tests'] , but "tests" isn't showing at all in the JSON result:

{"details":["Clinical result","Signature result"]}

$data = array();

while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
foreach($row['lab_test_group_fk'] as $group){
$data['tests'] = array($group);
}
}
echo json_encode($data);

If I change the above to the following then I get only the last record for $row['lab_test_group_fk'] , not all three records for that column (hence the foreach loop as above):

while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
$data['tests'] = array($row['lab_test_group_fk']);
}
echo json_encode($data);

{"details":["Clinical result","Signature result"],"tests":["21"]}

What am I doing wrong here?

Thanks to Tamil Selvin this was the solution that worked for me:

$data = array();

while ($row = mysql_fetch_array($result)) {
$data['details'] = array($row['tests_clinical'], $row['signature']);
$data['tests'][] = array($row['lab_test_group_fk']);
}
echo json_encode($data);

Which returned:

{"details":["Clinical result","Signature result"],"tests":[["31"],["2"],["21"]]}

Answer 1

$data['tests'] = array($group); means reassign $data['tests'] to a new value again.

Try $data['tests'][] = array($group); .

Answer 2

Try

$data = array();
while ($row = mysql_fetch_array($result)) {
  $data[]['details'] = array($row['tests_clinical'], $row['signature']);
  $data[]['tests'] = array($row['lab_test_group_fk']);
}
echo json_encode($data);

or

while ($row = mysql_fetch_array($result)) {
$data[] = array(
     'details' => array($row['tests_clinical'], $row['signature']),
      'tests' => array($row['lab_test_group_fk'])
);
}
echo json_encode($data);

Answer 3

You are overwriting existing data of $data. You need some kind of array where you will put all your records. Try this

$data = array();

while ($row = mysql_fetch_array($result)) {

    $record = array();   // this creates new record
    $record['details'] = array($row['tests_clinical'], $row['signature']);
    foreach($row['lab_test_group_fk'] as $group){
         $record['tests'] = array($group);
    }
    $data[] = $record;     // this adds record to data
}
echo json_encode($data);