[英]ignore column in minus statement
I am unable to find a solution to this problem. 我无法找到解决此问题的方法。
There are two tables to minus from each other. 有两个表相互减去。
Select columnA, columnB, columnC from tableA
minus
Select columnA, columnB, columnC from tableB
I need the data from tableA.columnC, however it will never match to tableB.columnC, so the minus statement will return both records. 我需要来自tableA.columnC的数据,但它永远不会与tableB.columnC匹配,因此minus语句将返回两个记录。
Is there a way to ignore columnC from the minus statement but still return the results? 有没有办法从minus语句中忽略columnC但仍返回结果?
-Thanks -谢谢
PS A little background on this problem. PS关于这个问题的一点背景。 I have a transaction table that list date of purchase, billed amount, item purchased (sometimes listed, sometimes not), account number of purchaser, and a unique identifier for the purchase.
我有一个交易表,列出购买日期,开单金额,购买的项目(有时列出,有时没有),购买者的帐号,以及购买的唯一标识符。
This table holds both purchases and reversals. 此表包含购买和撤消。 So if someone bought a item for 10.00 and then returns the item there is a -10.00 for that.
因此,如果有人为10.00购买了一件物品,然后返回该物品则为-10.00。 In some cases a person will buy, return, and buy that item again within the same day.
在某些情况下,某人会在同一天内再次购买,退货和购买该商品。 This data is from a third party.
此数据来自第三方。
Unfortunately a sum does not work in this case I need a line by line detail of all purchases that have not been reversed. 不幸的是,在这种情况下,总和不起作用我需要一行一行的详细信息,所有购买都没有被撤消。
I was able to get the correct data by following this posts advice and using a: Prevent Oracle minus statement from removing duplicates 通过遵循这些帖子建议并使用: 防止Oracle减去语句删除重复项,我能够获得正确的数据
However there is more information that I need from this table than just the information that I am using to minus off the returns. 但是,我需要从这个表中获得更多信息,而不仅仅是我用来减去回报的信息。
This is why i would like help with the above statement. 这就是为什么我想要帮助上述声明。
something on these lines should work: 这些行上的东西应该有效:
Select columnA, columnB, columnC from tableA a
where not exists
(Select 1 from tableB b where a.columnA=b.columnA and a.columnB=b.columnB)
Try this: 尝试这个:
select cola,colb,colc from tableA as A
inner join
(select cola,colb from tableA
minus
select cola,colb from tableB) as B
on a.cola = b.cola
and a.colb = b.colb;
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