PHP ：：清洁preg_match_all结果

Question

I'm trying to fetch a value from external html page.

Now this do the magic for me :

preg_match_all('/id="localWeather">(.*?)<\/div>/',$returnedPage,$returnValues,PREG_SET_ORDER);

But after this line I need to loop the results and clean it.

Why? because I only need this (.*?) and for some reason it return also add the extra </div> closing tag so I need to loop it and clean the array afterwards.

My question is how do I force to return only this : (.*?) ?

Answer 1

Get rid of PREG_SET_ORDER . Example:

<?php

$returnedPage = '<div id="localWeather">test</div><div id="localWeather">test2</div>';

preg_match_all('/id="localWeather">(.*?)<\/div>/',$returnedPage,$returnValues);

print_r($returnValues);

Output:

Array
(
    [0] => Array
        (
            [0] => id="localWeather">test</div>
            [1] => id="localWeather">test2</div>
        )

    [1] => Array
        (
            [0] => test
            [1] => test2
        )

)

So in this case, $returnValues[1] is an array of matches with just the content in between the divs (and not the closing div), while $returnValues[0] is an array of the entire portion of the string that matched your regex.

Also, using regular expressions isn't recommended to parse HTML. I'd look at PHP's DOMDocument class instead, it's more robust.