为什么在添加while循环以及if语句之后添加UnboundLocalError？

Question

Whats going on here? It's a basic slot machine game but when i try and add my conditions for the coins and coin generating I get the UnboundLocalError . The random numbers generate when i don't have my while loop and if then else if statements

import random

def main():
    coins = 50
    x = 0
    y = 0
    z = 0
    while coins >= 0 or giveUp != yes:
        coins = (coins - 3)
        x = random.randrange(1, 7)
        y = random.randrange(1, 7)
        z = random.randrange(1, 7)
        x = x
        y = y
        z = z
        print (x + y + Z)
        if (x == y) or (x == z):
            if (x == 1):
                coins = (coins + 3)
                print ("you win 3 coins")
            elif x == 2:
                coins = (coins +3)
                print = ("you win 3 coins")
            elif x == 3:
                coins = (coins + 3)
                print = ("you win 3 coins")
            elif x == 4:
                coins = (coins +3)
                print = ("you win 3 coins")
            elif x == 5:
                coins = (coins + 3)
                print = ("you win 3 coins")
            elif x == 6:
                coins = (coins + 3)
                print = ("you win 3 coins")
            elif x == 7:
                coins = (coins + 3)
                print = ("you win 3 coins")
            giveUp = (input("do you give up?"))

main()

Answer 1

This assignment (also called "binding")

giveUp = (input("do you give up?"))

means giveUp is a local.

The while loop is trying to test this local variable before you have assigned to it (ie bound it)

You could fix this by setting giveUp = "No" before the while loop

Also the yes should probably be "yes"

Answer 2

while coins >= 0 or giveUp != yes:

In here your loop condition is up to a variable called giveUp , but you're trying to define that variable in the loop. You have to define it before the loop first. The best solution is define giveUp="No" before the while loop. Also input() returns string so it must be;

giveUp="No"
while coins >= 0 or giveUp != "yes":
#codes

Another tip, you're using or operator, so if user type no even without any coins user still can play. You should change it to and ;

while coins >= 0 and giveUp != "yes":

Now if user want to play, need coins and 'yes'

Answer 3

Please correct your code... print (x + y + Z) name Z in your code is Upper. Sure error in here.. and print = name print should not follow the character =

Try this..

>>> import random
>>> def main():
    coins = 50
    x = 0
    y = 0
    z = 0
    while coins >= 0 or giveUp != yes:
        coins = (coins - 3)
        x = random.randrange(1, 7)
        y = random.randrange(1, 7)
        z = random.randrange(1, 7)
        x = x
        y = y
        z = z
        print (x + y + z)
        if (x == y) or (x == z):
            if (x == 1):
                coins = (coins + 3)
                print ("you win 3 coins")
            elif x == 2:
                coins = (coins +3)
                print ("you win 3 coins")
            elif x == 3:
                coins = (coins + 3)
                print ("you win 3 coins")
            elif x == 4:
                coins = (coins +3)
                print ("you win 3 coins")
            elif x == 5:
                coins = (coins + 3)
                print ("you win 3 coins")
            elif x == 6:
                coins = (coins + 3)
                print ("you win 3 coins")
            elif x == 7:
                coins = (coins + 3)
                print ("you win 3 coins")
            giveUp = (input("do you give up?"))


>>> main()
you win 3 coins
do you give up?3
12
12
9
7
12
9
14
10
15
you win 3 coins
do you give up?1
9
>>>