计算目录中每个文件中的markdown链接

Question

I am trying to figure out how to count and display the number of markdown links in each file in a directory.

For an individual file, I can use grep and wc :

grep -o -P "\[.*?\]\(.*?\)" file1.md | wc -l

But how can I do this individually for every file in a directory? The following (and variations using ls and other commands) gives me a total for all files:

find . -name "*.md" | xargs grep -o -P "\[.*?\]\(.*?\)" | wc -l

Ultimately I would like something that resulted in a list showing the filename and the number of matches returned by grep, something like:

file1: 7
file2: 11

Though the exact formatting of the result isn't important

Answer 1

How about a simple for loop?

for file in *.md
do
    echo -n ${file};grep -o -P "\[.*?\]\(.*?\)" ${file} | wc -l
done

Answer 2

Would the -c option, which produces a count of matches, be of help? as in

find . -name "*.md" | xargs grep -oc -P "\[.*?\]\(.*?\)" 

Answer 3

Can you try this one:

grep -o -P "\[.*?\]\(.*?\)" *md | cut -d ":" -f 1 | sort | uniq -c

it will give output like this:

     7 file1
    11 file2

If you want, you can transform output using sed