简体   繁体   English

wp_nav_menu中的自定义菜单标签

[英]Custom menu tags in wp_nav_menu

I've been trying to get the function wp_nav_menu() to output the following html structure: 我一直在尝试获取函数wp_nav_menu()来输出以下html结构:

 <ul> <li><a href="#">LINK</a></li><span>element</span> <li><a href="#">LINK</a></li><span>element</span> <li><a href="#">LINK</a></li><!--no element HERE!--> </ul> 

I tried with parameters like 'after' and 'link_after'. 我尝试使用'after'和'link_after'之类的参数。 But the first one outputs the element before </li> tag and the next one before </a> tag. 但是第一个输出</li>标记之前的元素,第二个输出</a>标记之前的元素。 Is there any way to output the <span> element after </li> tags? 有什么方法可以在</li>标记后输出<span>元素? I read about the Walker class but I don't quite understand its logic - I'm not that good at PHP. 我了解了Walker类,但是我不太了解它的逻辑-我不太擅长PHP。

I have no wp installed to test it, but still leave it here. 我没有安装wp对其进行测试,但仍将其保留在此处。 You need to extend the Walker_Nav_Menu class, like this: 您需要扩展Walker_Nav_Menu类,如下所示:

class custom_walker_nav_menu extends Walker_Nav_Menu 
{
    public function end_el( &$output, $item, $depth = 0, $args = array())
    {
        $output .= "</li><span>element</span>\n";
    }
}

And then pass new custom_walker_nav_menu as $walker parameter for wp_nav_menu() function. 然后将new custom_walker_nav_menu传递为wp_nav_menu()函数的$walker参数。 Actually, this answer is uncomplete, can't get how to get rid off last <span> element you don't need. 实际上,这个答案是不完整的,无法摆脱您不需要的最后一个<span>元素。 I'll try to improve it later. 稍后我会尝试改善它。 Also as @ rnevius mentioned in his comment it would be an invalid HTML, so you should definately use one of after or link_after . 就像@ rnevius在他的评论中提到的那样,这将是无效的HTML,因此,您必须使用afterlink_after

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM