如何使用sed或awk在单独的文件中grep带有模式的行

Question

I've a big data file ( data.txt ) and a pattern file ( patt.dat ) and the data is like below

data.txt

[bottle]:[some description 1]    
[pen]:[some description 2]    
[mobile]:[some description 3]       
[pen_pencil]:[some description 4]  
[mouse]:[some description 5]    

patt.dat

pen    
mobile    

i give like this

grep -F -f patt.dat data.txt    

then i get the below

[pen]:[some description 2]    
[mobile]:[some description 3]    
[pen_pencil]:[some description 4]    

but I want only want,

[pen]:[some description 2]    
[mobile]:[some description 3] 

Please help with any solution.
I don't want to hard code anything because there'll be a lot of such patterns and hard-coding all won't look good.

If the same can be achieved in any other way possibly, please suggest that one too.

Answer 1

Use -w for word match as well like:

grep -wf patt.dat data.txt 
Output:
[pen]:[some description 2]
[mobile]:[some description 3]

Answer 2

sed 's/.*/^\[&]/' patt.dat > /tmp/patt_grep.dat
egrep -F -f /tmp/patt_grep.dat data.txt

need to change a bit the patt.dat content to allow another efficient tool to work. I use egrep to allow the ^ but a (f)grep could be used changing the to format [word]:[ instead

Answer 3

Here is how to do it with awk

awk -F"[][]" 'FNR==NR {a[$1];next} $2 in a' patt.dat data.txt
[pen]:[some description 2]
[mobile]:[some description 3]

If you like to test on more parameters, awk may be the simplest solution.
It stores the pattern in array a , then test if field 2 is found in array a , if found, print the line.