有效地计算php中返回的结果

Question

Technologies in use: php accessing MySQL via PDO. 使用的技术：php通过PDO访问MySQL。

I have the following query: 我有以下查询：

    try {
        $stmt = $conn->prepare("SELECT * FROM $database.appsLodged WHERE `uID` = :uid");
        $stmt->bindValue(':uid', $uid);
        $stmt->execute();
        $result = $stmt->fetchAll();
    } catch(PDOException $e) { catchMySQLerror($e->getMessage()); }

Which is fairly straight forward. 这是相当简单的。 At the moment there are 7 rows in the relevant database, and each one can potentially have a different string value returned for $result[0][5]. 目前，相关数据库中有7行，每行可能为$ result [0] [5]返回不同的字符串值。 I would like to be able to count how many results there are that have a $result[0][5] of "shoes and socks" and then how many have a $result[0][5] of "boots and skirts" and how many have a $result[0][5] of "jumpers and cardigans" - without having to resort to doing multiple database queries (I know we can do it by adding an additional "AND item = :item" syntax and binding :item to "shoes and socks", but this seems very repetitive and unnecessary. 我希望能够计算出有$ result [0] [5]为“鞋子和袜子”的结果有多少，然后有$ result [0] [5]为“靴子和裙子”的结果为多少以及有多少个具有$结果[0] [5]的“跳线和开襟衫”-无需诉诸多个数据库查询（我知道我们可以通过添加其他“ AND item =：item”语法和绑定来做到这一点：item为“鞋子和袜子”，但这似乎非常重复且不必要。

Suggestions please, all welcome! 请提出建议，一切欢迎！ :) :)

C C

As requested below, here is the $result array listed: 按照下面的要求，这是列出的$ result数组：

Important to remember - it is actually the 'status' column I am wanting to count which for all of these examples except the first, is set to "Data Acquisition". 重要的是要记住-实际上，我想对“状态”列进行计数，除第一个示例外，所有这些示例的“状态”列均设置为“数据采集”。 The first is set to "Pending". 第一个设置为“待处理”。 There are another three values this could be, and if these are not in the database at the time I need a zero count for them so the user knows they have zero data set to other potential 'status' settings. 可能还有另外三个值，如果当时这些值不在数据库中，则我需要为它们提供零计数，以便用户知道将零数据设置为其他可能的“状态”设置。

Answer 1

I suggest you do the following: first of all, you take from you database all those strings, so you will have something like $result[0][5] , $result[1][5] , $result[2][5] and so on, then you foreach() them and match the strings in different variables, one for each string you want to match... I think, based on what you said in you query, that each uID has one type of string in the [5] position. 我建议您执行以下操作：首先，从数据库中获取所有这些字符串，因此您将拥有类似$result[0][5] ， $result[1][5] ， $result[2][5] ，依此类推，然后将它们foreach()匹配，并在不同的变量中匹配字符串，对于每个要匹配的字符串，一个...我想根据您在查询中所说的，每个uID都有一种字符串位于[5]位置。 In witch case, I advice you have a string of id's, so your query becomes something like this: 在女巫的情况下，我建议您有一个id的字符串，因此您的查询将如下所示：

$uid = '1,2,3,4,5'; // for example
$stmt = $conn->prepare("SELECT * FROM $database.appsLodged WHERE `uID` IN (:uid)");

$stmt->bindValue(':uid', $uid);

you will probably need one extra query to take all those ids but that's about it :D 您可能需要一个额外的查询来获取所有这些ID，仅此而已：D

Hope this helps! 希望这可以帮助！

有效地计算php中返回的结果

问题描述

1 个解决方案

解决方案1
0 2015-01-27 12:43:56

有效地计算php中返回的结果

问题描述

1 个解决方案

解决方案1 0 2015-01-27 12:43:56

解决方案1
0 2015-01-27 12:43:56