从列表设置路径的Pythonic方式

Question

I've been trying to make a program for my brother. One of the components of this would be to play an audio file. I have a list of about 90 audio files (please don't ask me why I have 90), and I am trying to randomly selected one and play it. However, to play it, I have to locate its path, and then plug the path into another section of my code (which I am still in the process of fixing). This is what I have so far:

import os, random

audio_playlist = [1, 2, 3, 4, ... all the way to 90]
sel_song = random.choice(audio_playlist)
song_path = None
base_directory = os.path.join(os.path.dirname(os.path.abspath(__file__)),
                                              "songs")

Right now, this is how I create the path of the randomly selected song:

while song_path == None:
    if sel_song == 1:
        song_path = os.path.join(directory, "1.mp3")
    elif sel_song == 2:
        song_path = os.path.join(directory, "2.mp3")
# and i do this 90 times... :(

Is there a more pythonic way of doing this? Also, how do I make this so that setting my song's path so that I don't have to be writing hundreds of lines of code, but rather using something that's very simple and is only about 10-15 lines of code. Also note that the file in song_path is basically just the number with .mp3 with it for simplicity.

Answer 1

You can directly have it as to create the path

if 1<= sel_song <=90:
    s.path.join(directory, "{}.mp3".format(sel_song))

And as emuiro suggested

audio_playlist = range(1, 91)

Is also a very Pythonic way

And as Padraic suggested,

audio_playlist = random.randint(1,91)

Is an even quicker way