[英]C program terminates when doing fwrite
So in this code what im trying to do is read the initial 44 bytes from a wave file put to a new file then calculate combination by using a sequence of left-right shorts 因此,在这段代码中,我想做的是从波形文件中读取最初的44个字节,然后将其放入新文件中,然后使用左右短裤的序列来计算组合
new file : (intial 44bytes - combination - combination - combination...) but it stops when I try to call fwrite. 新文件:(初始44字节-组合-组合-组合...),但是当我尝试调用fwrite时它停止了。
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[]) {
FILE * firstFile;
FILE * finalFile;
size_t size;
char *buffer;
short left;
short right;
short combination;
int loop;
printf("%s", argv[1]);
if ((firstFile = fopen("test.wav", "rb")) == NULL) {
printf("File error");
exit(1);
}
fseek(firstFile, 0, SEEK_END);
size = ftell(firstFile);
fseek(firstFile, 0, SEEK_SET);
buffer = malloc(44);
fread(buffer, 1, 44, firstFile);
finalFile = fopen("new.wav", "rb");
fwrite(&buffer, sizeof(buffer), 1, finalFile);
loop = 1;
while (loop == 1) {
fread(&left, sizeof(short), 1, firstFile);
if (fread(&right, sizeof(short), 1, firstFile) == 0) {
loop = 0;
}
combination = (left - right) / 2;
fwrite(&combination, sizeof(short), 1, finalFile);
}
fclose(firstFile);
fclose(finalFile);
free(buffer);
return 0;
}
You forgot to test the failure of fopen
like: 您忘了测试
fopen
的失败,例如:
finalFile = fopen("new.wav", "wb");
if (!finalFile) { perror("new.wav"); exit(EXIT_FAILURE); }
And if you write a file, open it in write mode. 并且,如果您写入文件,则以写入模式打开它。
You should of course compile with all warnings & debug info: 您当然应该编译所有警告和调试信息:
gcc -Wall -Wextra -g yoursource.c -o yourbinary
and use the debugger ( gdb
) 并使用调试器(
gdb
)
You just opened write file in "rb" mode. 您刚刚以“ rb”模式打开了写入文件。
finalFile = fopen("new.wav", "rb");
Please try 请试试
finalFile = fopen("new.wav", "wb");
and check 并检查
finalFile==NULL
Please open file in Write mode , Like "wb" 请以写入模式打开文件,如“ wb”
finalFile = fopen("new.wav", "wb");
then you have to check the return values 那么你必须检查返回值
You opened file in read mode. 您以读取模式打开文件。 That's why this issue happened, per the man page of fopen .
这就是为什么根据fopen的手册页会发生此问题的原因。 Please try write mode.
请尝试写入模式。
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