在C / C ++中将指针作为参数传递？

Question

How would one go about using the pointer parameter if given a function like this:

int testFunction(int *){  
}

I understand that a pointer is being passed as the parameter, but how do I use that pointer given that there is no variable name after the pointer?

Answer 1

You should name the argument. See this link for a tutorial

Answer 2

Name of function parameters can be omitted from function prototypes (declarations)

int testFunction(int *);  

You can't omit name of parameters from function definition.

Answer 3

You can get parameters from function's stack.

Before your function called, your program pushes parameters to stack. So you can define some internal variable in your function, and pop this parameter from stack into this variable.

For more information you have to research how do C functions work.