[英]Static member in header-only library
I'm creating header-only library and I have to use static member. 我正在创建仅限标头的库,我必须使用静态成员。
Is it possible to define it in the header file without redefinition warning? 是否可以在头文件中定义它而不重新定义警告?
Assuming you're talking about a static data member, since a static function member is no problem, there are various techniques for different cases: 假设您正在谈论静态数据成员,因为静态函数成员没有问题,针对不同情况有各种技术:
Simple integral type, const
, address not taken: 简单的整数类型, const
,地址未采取:
Give it a value in the declaration in the class definition. 在类定义的声明中为它赋值。 Or you might use an enum
type. 或者您可以使用enum
类型。
Other type, logically constant: 其他类型,逻辑上不变:
Use a C++11 constexpr
. 使用C ++ 11 constexpr
。
Not necessarily constant, or you can't use constexpr
: 不一定是常数,或者你不能使用constexpr
:
Use the templated static trick, or a Meyers' singleton. 使用模板化的静态技巧或Meyers的单例。
Example of Meyers' singleton: 迈耶斯单身人士的例子:
class Foo
{
private:
static
auto n_instances()
-> int&
{
static int the_value;
return the_value;
}
public:
~Foo() { --n_instances(); }
Foo() { ++n_instances(); }
Foo( Foo const& ) { ++n_instances(); }
};
Example of the templated statics trick: 模板化静态技巧的示例:
template< class Dummy >
struct Foo_statics
{
static int n_instances;
};
template< class Dummy >
int Foo_statics<Dummy>::n_instances;
class Foo
: private Foo_statics<void>
{
public:
~Foo() { --n_instances; }
Foo() { ++n_instances; }
Foo( Foo const& ) { ++n_instances; }
};
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