[英]Python 2.0.7, write some values to csv file row by row
I have a lot of lists, each with twelve values: 我有很多列表,每个列表都有十二个值:
["0.0051", "-0.0351", ..., "0.0325"] [“ 0.0051”,“-0.0351”,...,“ 0.0325”]
["0.0065", "0.0014", ..., "0.0851"] . [“ 0.0065”,“ 0.0014”,...,“ 0.0851”]。 .
。 .
。 ["0.0151", "0.0512", ... , "0.00917"]
[“ 0.0151”,“ 0.0512”,...,“ 0.00917”]
Each list has a id number that is like 2, 4, 7, 9... 每个列表的ID号都类似于2、4、7、9 ...
I want to write this list to a csv file row by row (if we see csv file by excel each row has 12 values and each row indicate the id_number) 我想将此列表逐行写到一个csv文件中(如果我们通过excel查看csv文件,则每行有12个值,每行表示id_number)
I just coded it like 我只是像这样编码
if existed_id != cur_id:
cur_ id = existed_id
value_list.append("/n")
with open ('outcome.csv', 'w') as csvfile:
g = csv.writer(csvfile, delimiter = ',')
data = value_list
g.writerow(data)
When run, it is not fully written in my csv file. 运行时,它没有完全写在我的csv文件中。 What's going wrong?
怎么了
If your records
are a list of lists od strings: 如果您的
records
是列表od字符串列表:
records = [["0.0051", "-0.0351", ..., "0.0325"],
["0.0065", "0.0014", ..., "0.0851"],
. . .
["0.0151", "0.0512", ... , "0.00917"]`
then the following code will write a csv file with len(records)
lines: 然后以下代码将用
len(records)
行写入一个csv文件:
with open('outcome.csv', 'w') as csvfile:
g = csv.writer(csvfile, delimiter=',')
for record in records:
g.writerow(data)
The with open...
line creates a new file (and overwrites a possibly previously existing file), so be sure you do not put it into a loop over records, because at the end only the last record would be saved into the file. with open...
行会创建一个新文件(并覆盖以前可能存在的文件),因此请确保不要将其放入记录循环中,因为最后只会将最后一条记录保存到文件中。
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