将带有方括号的字符串转换为列表，其中合并了方括号内容

Question

I want to transform the following string:

[test1 test2] test3 [test4 test5] test6 test7 [test8]

into the following array:

test1 test2, test3, test4 test5, test6, test7, test8

I have tried allot of things allready from $.grep to regEx. But it's just not cutting it. The closest I have come is the following:

var block_parts = text.match(/[^[\]]+(?=])/g);
var rest = text.replace(/ *\[[^\]]*]/g, '').split(" ");
var complete = $.merge(rest, block_parts);

But then it's not in the same order. (it will attach block_parts after rest)

Does anybody have an idea how I can do this?

Answer 1

Use double replace function. \\] +| +\\[ \\] +| +\\[ would match all the ] plus the following one or more space and also the closing [ along with the preceding spaces. Just replace those matched characters with ,<space> and again replace [ , ] with an empty string.

> var s = "[test1 test2] test3 [test4 test5] test6 test7 [test8]"
undefined
> var m = s.replace(/\] +| +\[/g, ", ").replace(/[\[\]]/g,'')
undefined
> console.log(m)
test1 test2, test3, test4 test5, test6 test7, test8

Update:

> var m = s.replace(/\] +| +\[|\s+(?!\w+\])/g, ", ").replace(/[\[\]]/g,'')
undefined
> console.log(m)
test1 test2, test3, test4 test5, test6, test7, test8