[英]Wrapping inner XML nodes with an outer node in TSQL
Take the following TSQL 采用以下TSQL
SELECT
o.id as '@id',
(SELECT
op.id as '@orderid'
FROM
Orders o
INNER JOIN
OrderParts op ON o.id = op.orderId
FOR XML PATH ('orderpart'), TYPE)
FROM
Orders o
FOR XML PATH ('order'), ROOT('application')
Generated from these tables. 从这些表生成。
Orders 命令
Id type
----------------
1 Pending
2 Active
Order Parts 订购零件
id orderid
-------------
1 1
2 1
3 3
4 2
It generates this XML 它生成这个XML
<application>
<order id="1">
<orderpart orderid="1" />
<orderpart orderid="2" />
<orderpart orderid="3" />
<orderpart orderid="4" />
</order>
<order id="2">
<orderpart orderid="1" />
<orderpart orderid="2" />
<orderpart orderid="3" />
<orderpart orderid="4" />
</order>
</application>
How do I add outer plural tags using TSQL around orders and orderparts so that it looks like the following? 如何在订单和订单部分周围使用TSQL添加外部复数标签,使其如下所示?
<application>
<orders>
<order id="1">
<orderparts>
<orderpart orderid="1" />
<orderpart orderid="2" />
<orderpart orderid="3" />
<orderpart orderid="4" />
</orderparts>
</order>
<order id="2">
<orderparts>
<orderpart orderid="1" />
<orderpart orderid="2" />
<orderpart orderid="3" />
<orderpart orderid="4" />
</orderparts>
</order>
</orders>
</application>
Thanks! 谢谢!
SELECT
(
SELECT o.id AS '@id',
(
SELECT op.id as '@orderid'
FROM OrderParts op
WHERE op.orderID = o.ID
FOR XML PATH ('orderpart'), TYPE
) AS 'OrderParts'
FROM Orders o
FOR XML PATH ('order'),TYPE
)
FOR XML PATH ('orders'),ROOT('application')
You're pretty close - just add and/or tweak a few column aliases here and there... 你非常接近 - 只需在这里添加和/或调整一些列别名......
SELECT
o.id as 'order/@id',
(SELECT
op.id as '@orderid'
FROM
Orders o
INNER JOIN
OrderParts op ON o.id = op.orderId
FOR XML PATH ('orderpart'), TYPE) AS 'order/orderparts'
FROM
Orders o
FOR XML PATH ('orders'), ROOT('application')
and that should do it! 应该这样做! :-) :-)
SAMPLE TABLES 样本表
CREATE TABLE #Orders(Id INT,[type] VARCHAR(100))
INSERT INTO #Orders
SELECT 1, 'Pending'
UNION ALL
SELECT 2, 'Active'
CREATE TABLE [#Order Parts](Id INT,orderid INT)
INSERT INTO [#Order Parts]
SELECT 1, 1
UNION ALL
SELECT 2, 1
UNION ALL
SELECT 3, 3
UNION ALL
SELECT 4, 2
QUERY QUERY
1. Using all possibilities for each Id(Your expected output) 1.使用每个Id的所有可能性(您的预期输出)
;WITH CTE(orderid,orderpartid) AS
(
SELECT ODR.id orderid ,ODRP.Id orderpartid
FROM #Orders ODR
CROSS JOIN [#Order Parts] ODRP
)
,CTE2 AS
(
-- This SELECT is used to name the xml data column
select
(
-- We take orders as the root node
select t1.orderid as 'order/@Id',
(
SELECT T.orderpartid '@orderid'
FROM CTE T
WHERE T.orderid=t1.orderid
FOR XML PATH('orderpart'), type
)as 'order/orderparts'
from CTE t1
group by t1.orderid
for xml path(''), root('orders')
)XMLDATA
)
-- We take application as the root node for orders
select CAST(XMLDATA AS XML)
FROM CTE2
for xml path('application')
RESULT 结果
2. Select matching elements for each Id 2.为每个Id选择匹配元素
;WITH CTE(orderid,orderpartid) AS
(
SELECT ODR.id orderid ,ODRP.Id orderpartid
FROM #Orders ODR
JOIN [#Order Parts] ODRP ON ODR.id = ODRP.orderId
)
,CTE2 AS
(
select
(
select t1.orderid as 'order/@Id',
(
SELECT T.orderpartid '@orderid'
FROM CTE T
WHERE T.orderid=t1.orderid
FOR XML PATH('orderpart'), type
)as 'order/orderparts'
from CTE t1
group by t1.orderid
for xml path(''), root('orders')
)XMLDATA
)
select CAST(XMLDATA AS XML)
FROM CTE2
for xml path('application')
RESULT 结果
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.