无法在数据库的表中插入值

Question

I am trying to insert values in database ,but not able to do that

<?php
if(isset($_POST['submit']))
{
$fullname=$_POST['fullname'];
$contactnumber=$_POST['contactnumber'];
$email=$_POST['email'];
$qualification=$_POST['qualification'];
$postappliedfor=$_POST['postappliedfor'];
$sql_connection=mysql_connect("localhost","root","admin","interview");
mysql_select_db("interview,$sql_connection") or die("cannot select DB");
$sql=mysql_query("INSERT INTO `USERDEATILS`(`id`,`fullname`,`contactnumber`,`email`,`qualification`,`postappliedfor`) VALUES('','$fullname','$contactnumber','$email','$qualification','$postappliedfor')");
if($sql){
        echo "done";
    }
    else{
        echo "There is an error!!"; 
    }
}


?>

Answer 1

change the line mysql_select_db("interview,$sql_connection")

to

mysql_select_db("interview", $sql_connection)

Answer 2

In addition to what Manuel Ramirez said, you might want to check to make sure your mysql data type 'id' isn't set to NOT NULL. You also may want add the to auto_increment property to the 'id' field, so you can ommit it when inserting records

Answer 3

Use proper syntax of mysql :

$sql_connection = mysql_connect('localhost', 'mysql_user', 'mysql_password');

remove database_name from mysql_connect .

In mysql_connect we can only pass 5 parameters :

1. Server
2. username
3. password
4. new_link
5. client_flags

But i will suggest you to use MySQLi that would be like this:

$connection = mysqli_connect('localhost', 'username', 'password', 'database');