Python - 匹配{}与正则表达式之间的子字符串出现

Question

I'm trying to search for one or more occurrences of a variable substring between two selectors "{" and "}" using regex. If it finds more than one, the output should be a list.

Here is an example of string :

mystring = "foofoofoo{something}{anything}foofoofoo"

This is the regex I use :

re.findall(r"^.*(\{.*\}).*$", mystring)

but it gives me the following output : {anything}

I've tried with r"(\\{.*\\})" and it returns me {something}{anything} which is almost good except it's not a list.

Any idea?

Answer 1

Remove anchors and .* from your regex to allow it to just capture from { to } :

>>> mystring = "foofoofoo{something}{anything}foofoofoo";
>>> re.findall(r"(\{[^}]*\})", mystring);
['{something}', '{anything}']

To skip { and } from matches, use captured groups:

>>> re.findall(r"\{([^}]*)\}", mystring);
['something', 'anything']

Answer 2

re.findall(r"({.*?})", mystring)

让你的*非贪心。