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在mysql列中选择包含字符串的行

[英]Select a row containing a string in a mysql column

I am trying to select all rows which contains string $places in a colum ADDRESS . 我试图在列ADDRESS选择包含字符串$places所有行。 here is what I coded but it only works when a cell only contains that string if there is other characters it wouldn't work 这是我编码的内容,但它只适用于单元格只包含该字符串的情况,如果有其他字符则不起作用

$sql = "SELECT *,CONCAT(mapLan,',',mapLon) as LatitudeLongitude FROM " . $table . " where ADDRESS like '$places' and SIZE between $firstrange and $secondrange";

For example $places = "East London" It would only select the row in which a cell only store East London and would leave alone the cells with Old Street, East London 例如$places = "East London"它只会选择一个单元格只存储East London的行,并且将单独留下Old Street, East London的单元格

What I want is to select all those rows which contains East London in Column ADDRESS 我想要的是在列ADDRESS选择包含East London所有行

You forget to use the % wildcard. 你忘了使用通配符。

meaning: 含义:
% Matches any number of characters, even zero characters 匹配任意数量的字符,甚至零个字符

$sql = "SELECT *,CONCAT(mapLan,',',mapLon) as LatitudeLongitude FROM " . $table . " where ADDRESS like '%$places%' and SIZE between $firstrange and $secondrange";

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