如何制作Java Shell命令（不使用Java运行Shell命令）

Question

I just finished an terminal program and cannot figure out how I can properly deploy it so it can be executed as such via bash:

myjavaprogram [options]

At best, I can only seem to get

java -jar /path/to/myjavaprogram [options]

to work. But this is insufficient. I'd like to give the program a clear name that I can quickly type. And before you say it, yes, I tried making a shell command already. It went as follows, and I named it what I wanted to name it:

#!/bin/bash
java -jar /path/to/myjavaprogram

I saved it to /usr/bin along with the other commands.

Problem is when I tried to run it, it wouldn't allow me to input options. Any advice from any java folks who have deployed a terminal application before? I don't want to have to type out the full path name each time I run the thing, as it is to be used for a very high volume purpose (lots of data crunching etc.). Any advice is appreciated. Thanks.

Answer 1

Sorry. HTML screwup there. I meant to say I want it to run like "myjavaprogram [options]" I used angle brackets accidentally.

Answer 2

If you want aa Bash solution, look into bash command line arguments. Generally you would use $1, $2, $3 etc to specify options, so in your case, if you want 3 options you would write this.

java -jar /path/to/myjavaprogram $1 $2 $3

and run it like so

my_prog 1 2 3

If you want to tell bash to process any other command line options given, use $@

java -jar /path/to/myjavaprogram $@

and run it liks so

my_proc 1 2 3 4 5 6 7 8 9 10

Answer 3

This should work

#! /bin/bash
exec java -jar /path/to/myjavaprogram "$@"

Notice the use of exec to discard bash and the quotes surrounding $@ to preserve whitespaces.

EDIT

Try this as your java program

public class T1 {
    public static void main(String args[]) {
        System.out.println(java.util.Arrays.toString(args));
    }
}