[英]Is there an elegant way to check multiple conditions?
I have multiple dropdown menus namely part_no,part_category,make and model. 我有多个下拉菜单,分别是part_no,part_category,make和model。 I am trying to display the quantity of vehicle parts in my inventory. 我试图在我的库存中显示车辆零件的数量。
Given that as I become more specific by supplying more values to the dropdown menu, the less type of part has to be displayed. 鉴于随着我通过向下拉菜单提供更多值而变得更具体,因此必须显示较少类型的部件。 (Something like a filtering) (像过滤一样)
A good example that I am trying to mimick are the dropdown menus found in this website: http://www.sgcarmart.com/used_cars/listing.php?MMO=Mini&RPG=20&MOD=Austin 我试图模仿的一个很好的例子是本网站的下拉菜单: http ://www.sgcarmart.com/used_cars/listing.php?MMO = Mini&RPG = 20 &MOD = Austin
Is there a better way of doing the checking(through all possible combinations) rather than doing this: 是否有更好的方法来进行检查(通过所有可能的组合)而不是这样做:
//Values from my dropdown menus
var carmake= $('#car_make').val();
var carmodel= $('#car_model').val();
var partname= $('#part_name').val();
var partcategory= $('#part_category').val();
if(carmake==data['carmake'])
{
//do something
}
else if (carmake==data['carmake'] && partname==data['partname'])
{
//do something
}
else if (carmodel==data['carmodel'] && partname==data['partname'])
{
//do something
}
else if (carmodel==data['carmodel'] && partname==data['partname'] &&partcategory==data['partcategory'])
{
//do something
} else if (carmodel==data['carmodel'] && partname==data['partname'] &&partcategory==data['partcategory' &&partname==data['partname'])
{
//do something
}
.
.
.
.
.
Put all your test values in an object whose property names are the same as in data
. 将所有测试值放在属性名称与data
相同的对象中。 Then loop over all the properties to see if they're all the same: 然后遍历所有属性以查看它们是否完全相同:
var search = {
carmake: $("#car_make").val(),
carmodel: $("#car_model").val(),
partname: $("#part_name").val(),
partcategory: $("#part_category").val()
};
var match = true;
$.each(search, function(prop, value) {
if (value !== "" && value != data[prop]) { // only compare if the dropdown was selected
match = false;
return false; // break out of the loop
}
});
if (match) {
// do something
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.