[英]Find out if file has been modified within the last 2 minutes
In a bash script I want to check if a file has been changed within the last 2 minutes.在 bash 脚本中,我想检查文件是否在过去 2 分钟内被更改。
I already found out that I can access the date of the last modification with stat file.ext -c %y
.我已经发现我可以使用
stat file.ext -c %y
访问上次修改的日期。 How can I check if this date is older than two minutes?如何检查此日期是否超过两分钟?
I think this would be helpful,我认为这会有所帮助,
find . -mmin -2 -type f -print
also,还,
find / -fstype local -mmin -2
Complete script to do what you're after:完整的脚本来做你所追求的:
#!/bin/sh
# Input file
FILE=/tmp/test.txt
# How many seconds before file is deemed "older"
OLDTIME=120
# Get current and file times
CURTIME=$(date +%s)
FILETIME=$(stat $FILE -c %Y)
TIMEDIFF=$(expr $CURTIME - $FILETIME)
# Check if file older
if [ $TIMEDIFF -gt $OLDTIME ]; then
echo "File is older, do stuff here"
fi
If you're on macOS
, use stat -t %s -f %m $FILE
for FILETIME
, as in a comment by Alcanzar.如果您使用的是
macOS
,请使用stat -t %s -f %m $FILE
for FILETIME
,如 Alcanzar 的评论中所述。
I solved the problem this way: get the current date and last modified date of the file (both in unix timestamp format).我通过这种方式解决了这个问题:获取文件的当前日期和上次修改日期(均采用 unix 时间戳格式)。 Subtract the modified date from the current date and divide the result by 60 (to convert it to minutes).
从当前日期中减去修改日期并将结果除以 60(将其转换为分钟)。
expr $(expr $(date +%s) - $(stat mail1.txt -c %Y)) / 60
Maybe this is not the cleanest solution, but it works great.也许这不是最干净的解决方案,但效果很好。
Here is how I would do it: (I would use a proper temp file)这是我的方法:(我会使用适当的临时文件)
touch -d"-2min" .tmp
[ "$file" -nt .tmp ] && echo "file is less than 2 minutes old"
Here's an even simpler version that uses shell math over expr:这是一个更简单的版本,它使用 shell 数学而不是 expr:
SECONDS (for idea)秒(想法)
echo $(( $(date +%s) - $(stat file.txt -c %Y) ))
MINUTES (for answer)分钟(用于回答)
echo $(( ($(date +%s) - $(stat file.txt -c %Y)) / 60 ))
HOURS小时
echo $(( ($(date +%s) - $(stat file.txt -c %Y)) / 3600 ))
Here is a solution that will test if a file is older than X seconds.这是一个测试文件是否早于 X 秒的解决方案。 It doesn't use
stat
, which has platform-specific syntax, or find
which doesn't have granularity finer than 1 minute.它不使用
stat
,它具有特定于平台的语法,或find
粒度不超过 1 分钟。
interval_in_seconds=10
filetime=$(date -r "$filepath" +"%s")
now=$(date +"%s")
timediff=$(expr $now - $filetime)
if [ $timediff -ge $interval_in_seconds ]; then
echo ""
fi
For those who like 1-liners once in a while:对于那些偶尔喜欢 1-liners 的人:
test $(stat -c %Y -- "$FILE") -gt $(($(date +%s) - 120))
This solution is also safe with any kind of file name, including if it contains %!"`' ()
此解决方案对于任何类型的文件名也是安全的,包括它是否包含
%!"`' ()
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