如何在外壳中使echo或printf忽略双反斜杠（\\\\）并按我看到的方式打印

Question

I'm trying to enter some ascii word art into my shell script and I'm using two backslashes (\\\\) together I want echo or printf to print both these backslashes together. Is there something I can put after echo or printf to make them literally print every character within the double quotes (")?

for example I want:

echo -something "
     __      __  __      __
      \\    //    \\    //
       \\  //      \\  //
        \\//        \\//
"

to print

     __      __  __      __
      \\    //    \\    //
       \\  //      \\  //
        \\//        \\//

Exactly how it is.

Answer 1

Single quotes are your friend; backslash is just an ordinary character inside a single-quoted string. So is every other character except single-quote itself.

echo '
     __      __  __      __
      \\    //    \\    //
       \\  //      \\  //
        \\//        \\//
'

If you needed single quotes in the single-quoted output, you have to write the sequence '\\'' to get the single quote:

echo '"single quotes" ('\'') are harder than "backslashes" (\)'

where I included double quotes and backslashes to make it harder to use double quotes around the string. However, you could also write:

echo "\"single quotes\" (') are harder than \"backslashes\" (\\)"