[英]How do make serialize / deserialize this entity?
The code below defines a dictionary used to transform field values. 下面的代码定义了一个用于转换字段值的字典。 Data is read, some of the values are transformed based on this dictionary, and written to a table.
读取数据,一些值根据此字典进行转换,然后写入表中。 It works as-is.
它按原样工作。 The problem, I now want to move this configuration outside the .py file into a JSON configuration file.
问题是,我现在想将此配置从.py文件外移到JSON配置文件中。
lookups = {
11: {
"ST1": ["ABC"],
"UNK01": ["125", "ACD"],
"A": ["52"],
"B": ["91"],
"C": ["92"],
"D": ["95"]
},
10: {
"XYZ01": ["91"],
"XYZ02": ["83"],
"XYZ03": ["27"]
}
}
According to jsonlint.com, in order for the above value being assigned to lookups
to be valid JSON, I must quote the 11
and 10
keys. 根据jsonlint.com,为了将上述值分配给
lookups
为有效的JSON,我必须引用11
和10
键。 Doing so breaks my Python code and displays TypeError: list indices must be integers, not str
. 这样做会破坏我的Python代码并显示
TypeError: list indices must be integers, not str
。
How do I create valid JSON and minimize changes to my code? 如何创建有效的JSON并最小化对代码的更改?
If you want to dump it to a json file: 如果要将其转储到json文件中:
import json
with open("config.json","w") as f:
json.dump(lookups, f) # dump dict to file
with open("config.json") as f:
s = json.load(f) # load dict from file
print(s)
{'11': {'ST1': ['ABC'], 'A': ['52'], 'D': ['95'], 'UNK01': ['125', 'ACD'], 'B': ['91'], 'C': ['92']}, '10': {'XYZ01': ['91'], 'XYZ03': ['27'], 'XYZ02': ['83']}}
If you need keys as ints you can loop and cast as ints or use pickle
: 如果您需要将键作为整数,则可以循环并转换为整数或使用
pickle
:
import pickle
with open("in.pkl","wb") as f:
pickle.dump(lookups, f)
with open("in.pkl","rb") as f:
s = pickle.load(f)
print(s)
{10: {'XYZ03': ['27'], 'XYZ01': ['91'], 'XYZ02': ['83']}, 11: {'UNK01': ['125', 'ACD'], 'B': ['91'], 'D': ['95'], 'ST1': ['ABC'], 'C': ['92'], 'A': ['52']}}
If not just use as is. 如果不按原样使用。
If you know what type of data your keys are, a simple int
on the keys would suffice: 如果您知道密钥是什么类型的数据,则只需对密钥进行简单的
int
就可以:
dictionary_from_json = json.loads(dumped)
newdict = {}
for key, val in dictionary_from_json:
newdict[int(key)] = val
You can extend json.decoder and convert all keys to int when it's possible. 您可以扩展json.decoder并将所有键转换为int(如果可能)。
import json
class Json(json.JSONDecoder):
def decode(self,json_string):
default_obj = super(Json,self).decode(json_string)
new_obj = self._rec_serial(default_obj)
return new_obj
def _rec_serial(self,default):
new_dict = {}
for key,value in default.items():
is_dict = isinstance(value,dict)
value = self._rec_serial(value) if is_dict else value
try:
new_dict[int(key)] = value
except ValueError:
new_dict[key] = value
return new_dict
json2= Json()
d = json2.decode(dumped)
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