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从结构中将字符串分配给char值

[英]Assigning a string to a char value from a struct

I'm trying to assign a string to a char value from a struct 我正在尝试从结构中将字符串分配给char值

typedef struct blah_param_s {
    struct blah_param_s*  param_next;
    blah_param_type_t     param_type;
} blah_param_t;

typedef struct blah_param_char_s {
    blah_param_t    param_hdr;
    char*           param_val;
} blah_param_char_t;

my function is: 我的功能是:

static inline char blah_get_param_char (blah_param_t* param_p)
{
    return (((blah_param_char_t*)param_p)->param_val);
}

And the offending code that kicks this all off is: 而这一切的令人讨厌的代码是:

((blah_param_char_t*)new_param_p)->param_val = value;

where value is "blah" 值是“等等”

Which give me a warning: return makes integer from pointer without a cast 给我一个警告:return从指针转换为整数而不进行强制转换

Now for integers it works: 现在,对于整数,它可以工作:

typedef struct blah_param_int_s {
    blah_param_t    param_hdr;
    uint32_t        param_val;
} blah_param_int_t;

static inline uint32_t blah_get_param_int (blah_param_t* param_p)
{
    return (((blah_param_int_t*)param_p)->param_val);
}

Any help would be really appreciated! 任何帮助将非常感激!

if you want to return the first character of the string from the function blah_get_param_char then use *(((blah_param_int_t*)param_p)->param_val) instead of (((blah_param_char_t*)param_p)->param_val); 如果要从函数blah_get_param_char返回字符串的第一个字符,请使用*(((blah_param_int_t*)param_p)->param_val)而不是(((blah_param_char_t*)param_p)->param_val);

Or, if you want to return the entire string then return as pointer ( char* ) to the string. 或者,如果要返回整个字符串,则以指针( char* )的形式返回该字符串。

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