[英]Assigning a string to a char value from a struct
I'm trying to assign a string to a char value from a struct 我正在尝试从结构中将字符串分配给char值
typedef struct blah_param_s {
struct blah_param_s* param_next;
blah_param_type_t param_type;
} blah_param_t;
typedef struct blah_param_char_s {
blah_param_t param_hdr;
char* param_val;
} blah_param_char_t;
my function is: 我的功能是:
static inline char blah_get_param_char (blah_param_t* param_p)
{
return (((blah_param_char_t*)param_p)->param_val);
}
And the offending code that kicks this all off is: 而这一切的令人讨厌的代码是:
((blah_param_char_t*)new_param_p)->param_val = value;
where value is "blah" 值是“等等”
Which give me a warning: return makes integer from pointer without a cast 给我一个警告:return从指针转换为整数而不进行强制转换
Now for integers it works: 现在,对于整数,它可以工作:
typedef struct blah_param_int_s {
blah_param_t param_hdr;
uint32_t param_val;
} blah_param_int_t;
static inline uint32_t blah_get_param_int (blah_param_t* param_p)
{
return (((blah_param_int_t*)param_p)->param_val);
}
Any help would be really appreciated! 任何帮助将非常感激!
if you want to return the first character of the string from the function blah_get_param_char
then use *(((blah_param_int_t*)param_p)->param_val)
instead of (((blah_param_char_t*)param_p)->param_val);
如果要从函数
blah_get_param_char
返回字符串的第一个字符,请使用*(((blah_param_int_t*)param_p)->param_val)
而不是(((blah_param_char_t*)param_p)->param_val);
Or, if you want to return the entire string then return as pointer ( char*
) to the string. 或者,如果要返回整个字符串,则以指针(
char*
)的形式返回该字符串。
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