如何管理结构类型为XPoint的向量？

Question

good evening. Yeah I'm a newbie in this world of C and C++. What should I do to solve this:

int i;
vector <XPoint> originales;
originales.reserve(7);
XPoint asteroid[5];
for(k = 0; k < 7; k++){
    for(i = 0; i < 5; i++){
        asteroid[i].x = rand() % 20 - 100;
        asteroid[i].y = rand() % 20 - 100;
    }
    originales.push_back(*asteroid);
}//end of first for

/*
    The XPoint structure contains:
    typedef struct {
        short x, y; 
    } XPoint; 
*/

When I print the coordinates are incomplete. Is this means that You can't save XPoint[] arrays inside a vector of XPoint?. In that case, how can I fix it? Please help!

Answer 1

Arrays and vectors are not compatible. The only thing you can push_back onto originales is an XPoint . But vector s already handle this sort of thing very well - they were made for it! - so you don't need the extra array at all:

for(k = 0; k < 7; k++){
    for(i = 0; i < 5; i++){
        XPoint asteroid;
        asteroid.x = rand() % 20 - 100;
        asteroid.y = rand() % 20 - 100;
        originales.push_back(asteroid);
    }
}