在Zend Framework 2中选择左连接变量

Question

I'm trying to do the following select in Zend Framework 2:

$select->from($this->table);
    $select->join($this->multiLangTable, $this->table . '.id=' .$this->multiLangTable . '.'
            . $this->foreignKey .' AND '. $this->multiLangTable . ".lang =".$locale, $mapping, 'left');

The variable $locale is the language of my application (ca, es, en). The problems is that the app shows and error saying :

Statement could not be executed (42S22 - 1054 - Unknown column 'ca' in 'on clause')

It detects the variable as a column, but it's not a column.

Answer 1

I have tried the same before but havent really found a good way to do it. this is because Zend just qoutes everything in the on statement as identifiers. You can just move the condition to the where statement

$select->from($this->table);
$select->join($this->multiLangTable, $this->table . '.id=' .$this->multiLangTable . '.'
            . $this->foreignKey, $mapping, \Zend\Db\Sql\Select::JOIN_LEFT);
$select->where(array($this->multiLangTable . ".lang" => $locale));

Or you can use a \\Zend\\Db\\Sql\\Expression in the on statement, but this will remove all the qouting from it.

$select->join($this->multiLangTable,new \Zend\Db\Sql\Expression($this->table . '.id=' .$this->multiLangTable . '.'
        . $this->foreignKey .' AND '. $this->multiLangTable . ".lang = ? ", $locale), $mapping, 'left');

Answer 2

I've found a solution that works for me.

 $select->from($this->table);
 $select->join($this->multiLangTable,new \Zend\Db\Sql\Expression( $this->table . '.id=' .$this->multiLangTable . '.'
            . $this->foreignKey . ' AND '.$this->multiLangTable . '.lang = ?'), $mapping, 'left');
 $statement = $sql->prepareStatementForSqlObject($select);

 $resultsSql = $statement->execute(array($locale));