如何在Java中查找用户输入的字符串是否为基本字符串文字？

Question

Here I've base String called String baseString = "nullpointer" ; if user entered some strings like pointernull , llpointer , internullpo then it should print TRUE else FALSE. How to write the logic for this? please help me.

public class literalString {
public static void main(String[] args) {
    String baseString = "nullpointer";
    Scanner sc = new Scanner(System.in);
    String input = sc.next();
    //pointernull, llpointer, internullpo  then return TRUE.
    // pointerllnu, unpointerll  then return FALSE
    //what shoul be the logic here?
 }
}

Your help will be appreciated.

Answer 1

First check baseString.length==input.length if it is fails then it is wrong if it is true then check using concat and contains

Simple example

String baseString = "nullpointer";
    Scanner sc = new Scanner(System.in);
    String input = sc.next();
    if(baseString.length()!=input.length()){
        System.out.println("false");
    }
    else{
        if(baseString.concat(baseString).contains(input)){
            System.out.println("true");
        }
        else{
            System.out.println("false");
        }
    }

Answer 2

Try something like this:

String[] valueList = {"pointernull", "llpointer", "internullpo"};

if(Arrays.asList(valueList).indexOf(input) != -1) {
    // User has typed "pointernull", "llpointer" or "internullpo"
}else{
    // User has typed something else
}

Answer 3

Simply:

(base.concat(base)).contains(input);

So if your base is nullpointer , then base.concat(base) will yield nullpointernullpointer , and contains will return true on nullp , pointernull , ointernu , etc.