Java用querystring打开网页

Question

I need to open web page after clicking button in my java window app. My problem is that when I use

URI testPage = new URI("file:///C:/index.html?param1&param2"); Desktop.getDesktop().browse(testPage);

opened page in my browser doesn't contain my querystring parameters, which are necessary to display page properly. How can I do that? Why is everything after "?" cut?

Answer 1

I don't think a file URI supports a query string. The query string is handled by the HTTP server, so unless you are running a server on your computer I don't think it will work.

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Answer 2

Your problem isn't in how java handles query strings, it is in how you local browser is handling file requests. A quick test of an HTTP URL shows that this works just fine. I tried this and it worked exactly as expected:

public class Test {
    public static void main(String[] args) throws IOException, URISyntaxException{
        URI test = new URI("http://google.com?test=monkey");
        Desktop.getDesktop().browse(test);
    }
}