将JSON数据引导到Scala PlayFramework模板中

Question

Goal is to go from a Model/ViewModel written in Scala to raw JSON that can be bootstrapped into the view template so as to avoid making requests for the JSON data after the page load. 目标是从用Scala编写的Model / ViewModel转换为可以引导到视图模板中的原始JSON，以避免在页面加载后发出对JSON数据的请求。

And example of what I've been playing around with but I haven't had much luck: 我一直在玩的例子，但我运气不好：

@(todos: play.api.libs.json.JsValue)
@import play.api.libs.json.Json

<html>
   <head>...</head>
   <body>...</body>

   <script>
      var todos = JSON.parse(' @Json.stringify(todos) ');
   </script>
</html>

Basically its spitting out a lot of quoted text to the effect of: 基本上它吐出了很多引用的文字，效果如下：

[{&quot;id&quot;:&quot;:&quot;294858e2-c9eb-4f50-9eac-47b257573d83&quot;}]

Haven't had much luck with Google or the PlayFramework docs so I'd love some help. 没有太多运气与谷歌或PlayFramework文档，所以我喜欢一些帮助。

Answer 1

The Play template engine will escape any strings you render to HTML, which will thoroughly mangle your JSON. Play模板引擎将转义您呈现给HTML的任何字符串，这将彻底破坏您的JSON。

To output it verbatim, do @Html(Json.stringify(todos)) , as described here . 为了输出逐字，做@Html(Json.stringify(todos))如所描述这里。

将JSON数据引导到Scala PlayFramework模板中

问题描述

1 个解决方案

解决方案1
8 已采纳 2015-02-11 00:02:54

将JSON数据引导到Scala PlayFramework模板中

问题描述

1 个解决方案

解决方案1 8 已采纳 2015-02-11 00:02:54

解决方案1
8 已采纳 2015-02-11 00:02:54