用数组PHP制作对象

Question

I am trying to search one word in my whole table. So if you search Eminem, you have to get everything with the word Eminem.

I search

<?php

 $sql="SELECT * FROM album WHERE albumartiest like '$zoek'";
    $resultaatcolumn = Yii::app()->db->CreateCommand($sql)->queryAll();                         
    if($resultaatcolumn != null){
     $zoekresultaat[] = $resultaatcolumn;}
 $sql="select * from album where albumnaam like '%$zoek%'";
    $resultaatcolumn = Yii::app()->db->CreateCommand($sql)->queryAll();
    if($resultaatcolumn != null){
     $zoekresultaat[] = $resultaatcolumn;}
 $sql="select * from album where albumartiest like '%$zoek%'";
    $resultaatcolumn = Yii::app()->db->CreateCommand($sql)->queryAll();
    if($resultaatcolumn != null){
     $zoekresultaat[] = $resultaatcolumn;}
 $sql="select * from album where albumgenre like '%$zoek%'";
    $resultaatcolumn = Yii::app()->db->CreateCommand($sql)->queryAll();
    if($resultaatcolumn != null){
     $zoekresultaat[] = $resultaatcolumn;}
 $sql="select * from album where albumafspeelijst like '%$zoek%'";
    $resultaatcolumn = Yii::app()->db->CreateCommand($sql)->queryAll();
    if($resultaatcolumn != null){
     $zoekresultaat[] = $resultaatcolumn;}

It works, but not exactly how I want it. The result is this:

Array ( [0] => Array ( [0] => Array ( [albumcode] => 45 [albumnaam] => recovery [albumafspeelijst] => ["Cold Wind Blows","Talkin' 2 Myself","On Fire","Won't Back Down","W.T.P.","Going Through Changes","Not Afraid","Seduction","No Love","Space Bound","Cinderella Man","To Life","So Bad","Almost Famous","Love The Way You Lie","You're Never Over",""] [albumartiest] => Eminem [albumgenre] => hip-hop [albumimage] => images\eminemrecovery.png [albumprijs] => 20 ) ) [1] => Array ( [0] => Array ( [albumcode] => 45 [albumnaam] => recovery [albumafspeelijst] => ["Cold Wind Blows","Talkin' 2 Myself","On Fire","Won't Back Down","W.T.P.","Going Through Changes","Not Afraid","Seduction","No Love","Space Bound","Cinderella Man","To Life","So Bad","Almost Famous","Love The Way You Lie","You're Never Over",""] [albumartiest] => Eminem [albumgenre] => hip-hop [albumimage] => images\eminemrecovery.png [albumprijs] => 20 ) ) )

that's okay, but what I want is take out variable's and use it.

is there a way that I can get variable's out of the array and use it? If you guys want more information about my code please ask!

Answer 1

Try using this

Yii::app()->db->CreateCommand($sql)->setFetchMode(PDO::FETCH_OBJ)->queryAll()

This will give you an array of objects with column name as the properties .

Eg:-

foreach($result as $row)
{
echo $row->albumcode;
}

Answer 2

If you want to access the result set like an object you can use the native PHP class ArrayObject and provide the flag to indicate that.

$album = new ArrayObject($result, ArrayObject::ARRAY_AS_PROPS);

You can now access the results like the following:

$code = $album->albumcode;
$name = $album->albumnaam;

Hope this can guide you, happy coding!

Answer 3

uhhh just do

foreach($zoekresultaat as $key => $value) {
   //do what I want with each seperate returened result. The array key is in $key and the result array is in $value
   echo $value['albumcode'] . ' = '. $value['albumnaam'];

}

aka, basic php

And please for the security of your app, learn how to do prepared statements in yii

The way your query is now I could wipe your entire database